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Alenkasestr [34]
3 years ago
9

Electromagnets are created using charged and insulated wire wrapped around a piece of iron. uncharged and insulated wire wrapped

around a piece of iron. insulated wire wrapped around a piece of plastic. charged and uninsulated wire wrapped around a piece of steel.
Chemistry
1 answer:
Inessa [10]3 years ago
8 0
I think the correct answer would be <span>charged and insulated wire wrapped around a piece of iron. The charge in the wire would make magnetic fields through the aid of the magnetic properties of iron. Hope this helps. Have a nice day.</span>
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Will a chlorine atom gain or lose electrons? <br> Gain or Lose
user100 [1]

Answer:

Chlorine (Cl) in its lowest energy state (called the ground state) has seven electrons in its outer shell. Again, it is more energy-efficient for chlorine to gain one electron than to lose seven. ... In the formation of an ionic compound, metals lose electrons and nonmetals gain electrons to achieve an octet.

Explanation:

3 0
3 years ago
PLEASE PLEASE HELP
Elina [12.6K]

add it up maybe?

Explanation:

4 0
4 years ago
If a gaseous sample contains 80.% N2 by volume, what is the solubility of N2 in water at 25°C and 1.0 atm (kH in H2O at 25°C = 7
Sedaia [141]

<u>Answer:</u> The solubility of nitrogen gas in the sample is 5.6\times 10^{-4}mol/L

<u>Explanation:</u>

We are given:

Volume percent of nitrogen gas = 80 %

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{N_2}=K_H\times p_{N_2}

where,

K_H = Henry's constant = 7.0\times 10^{-4}mol/L.atm

p_{N_2} = partial pressure of nitrogen gas = 1.0 atm

Putting values in above equation, we get:

C_{N_2}=7.0\times 10^{-4}mol/L.atm\times 1.0\\\\C_{N_2}=7.0\times 10^{-4}mol/L

Solubility of nitrogen gas in the sample = \frac{80}{100}\times 7.0\times 10^{-4}mol/=5.6\times 10^{-4}mol/L

Hence, the solubility of nitrogen gas in the sample is 5.6\times 10^{-4}mol/L

4 0
3 years ago
How many atoms of each element are in Copper Sulfate (CuSO4)? Name the elements and the number of atoms for each element.
Sati [7]
Hey☺..Here is your answer u r looking for
Copper (Cu) = 1 atom
Sulphur(S)=1 atom
Oxygen(O)= 4 atom
8 0
3 years ago
Read 2 more answers
How many atoms of Ca are present in 80.156 grams of Ca?
Semenov [28]

The number of atoms present in 80.156 grams of Ca is 1.204×10²⁴ atoms

<h3>Avogadro's hypothesis </h3>

From Avogadro's hypothesis,

1 mole of Ca = 6.02×10²³ atoms

But

1 mole of Ca = 40.078 g

Thus,

40.078 g of Ca = 6.02×10²³ atoms

<h3>How to determine the atoms in 80.156 g of Ca</h3>

40.078 g of Ca = 6.02×10²³ atoms

Therefore,

80.156 g of Ca = (80.156 × 6.02×10²³) / 40.078

80.156 g of Ca = 1.204×10²⁴ atoms

Thus, 1.204×10²⁴ atoms is present in 80.156 g of Ca.

Learn more about Avogadro's number:

brainly.com/question/26141731

8 0
3 years ago
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