Answer: Sheila's top brick will be cooler than Ralph’s top brick, because Sheila’s started with more total energy, so less energy had to transfer for both her bricks to reach the same total energy.
Explanation:
The phosphate concentration of the unknown sample is <u>0.002 M</u>
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Beer's law, the quantity of power absorbed or transmitted by using a solution is proportional to the solution's molar absorptivity and the awareness of the solute. In easy terms, a greater focused answer absorbs greater light than a more dilute solution does.
C = εa/b
= 0.285 / 137.2
=<u> 0.002 M</u>
A sequence of fashionable solutions containing a purple dye was made by diluting an inventory answer and then measuring the percent transmittance of every answer at 505 nm (greenish blue). This wavelength became decided on with the aid of examining its absorption spectrum.
Lambert's law of absorption states that equal elements inside the equal absorbing medium soak up identical fractions of the mild that enters them. If in traversing a path of duration dx the intensity is decreased.
Learn more about beer's law here:-brainly.com/question/18591932
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The half-life of a radioactive compound is the time taken for that said isotope to decay or disintegrate so that only half of the initial atoms remain in that compound. During the decay process, the isotope will give off energy and matter, and the way to depict this is indicated by t 1/2.
Complete Question:
This diagram shows a marble with a mass of 3.8 grams (g) that was placed into 10 milliliters (mL) of water. Using the formula V M D = , what is the density of the marble?
(See attachment for full diagram)
Answer:
1.27 g/cm³
Explanation:
First, find the volume of rock:
Volume of rock = volume of water after rock was placed - volume of water before rock was placed
Volume of rock = 13 - 10 = 3ml
Density of rock = grams of rock per 1 cm³
Note: 1 ml = 1 cm³
Let x represent amount of rock per 1 cm³
Thus,
3.8g = 3 cm³
x = 1 cm³
Cross multiply
1*3.8 = 3*x
3.8 = 3x
3.8/3 = 3x/3
1.27 = x
Density of rock = 1.27 g/cm³
