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Strike441 [17]
3 years ago
14

An FM radio station broadcasts electromagnetic radiation at a frequency of 103.4 MHz (megahertz; MHz =106s–1). Calculate the w

avelength of this radiation. The speed of light is 2.998 × 108m/s to four significantdigits.
Chemistry
1 answer:
kap26 [50]3 years ago
5 0

Answer:

Wavelength=2.899\ m

Explanation:

The relation between frequency and wavelength is shown below as:

c=frequency\times Wavelength

c is the speed of light having value 2.998\times 10^8\ m/s

Given, Frequency = 103.4 MHz = 103.4\times 10^{6}\ Hz  ( as 1 MHz = 10⁶ Hz)

Thus, Wavelength is:

Wavelength=\frac{c}{Frequency}

Wavelength=\frac{2.998\times 10^8}{103.4\times 10^{6}}\ m

Wavelength=2.899\ m

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A laboratory analysis of a sample finds it is composed of 38.8% carbon, 16.2% hydrogen, and 45.1% nitrogen. What is its empirica
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Answer: The empirical formula for the given compound is CH_5N

Explanation : Given,

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Let the mass of compound be 100 g. So, percentages given are taken as mass.

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Mass of H = 16.2 g

Mass of N = 45.4 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{38.8g}{12g/mole}=3.23moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{16.2g}{1g/mole}=16.2moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{45.4g}{14g/mole}=3.24moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.

For Carbon = \frac{3.23}{3.23}=1

For Hydrogen  = \frac{16.2}{3.23}=5.01\approx 5

For Oxygen  = \frac{3.24}{3.23}=1.00\approx 1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 1 : 5 : 1

Hence, the empirical formula for the given compound is C_1H_5N_1=CH_5N

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A 0.0300 M NaCl solution was formed when 42.0 grams of NaCl was dissolved in enough water. What was the total volume of the solu
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Answer:

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