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Sonja [21]
3 years ago
11

What does the graph of data from the Moana Loa lab indicate about the level of CO2 in the atmosphere in 1960 compared to the pre

sent?
Chemistry
1 answer:
lawyer [7]3 years ago
3 0

I don't know the answer honestly

Explanation:

cuz like why

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Im stuck pls help me!!
Ratling [72]

Answer:

I would say the amount of sunlight, nutrients and the amount of time the weeds are pulled

Explanation:

That’s what l believe it is.

3 0
3 years ago
How many grams are there in 1.5x1025 molecules of hydrogen gas (H2)?
alexandr402 [8]

Answer:

1537.5

Explanation:

3 0
3 years ago
4. A 14.5-L balloon is in the air where it is 20.0 C at 0.980-atm. A wind passes over and the balloon's pressure becomes 740.0-m
jeka94

The temperature of the wind as that decreases the volume and the pressure of the balloon to the given values is 14.09°C.

<h3>What is Combined gas law?</h3>

Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

P₁V₁/T₁ = P₂V₂/T₂

Given the data in the question;

  • Initial volume V₁ = 14.5L
  • Initial pressure P₁ = 0.980atm
  • Initial temperature T₁ = 20.0°C = 293.15K
  • Final volume V₂ = 14.3L
  • Final pressure P₂ = 740.mmHg = 0.973684atm
  • Final temperature T₂ = ?

We substitute our given values into the expression above.

P₁V₁/T₁ = P₂V₂/T₂

( 0.980atm × 14.5L )/293.15K = ( 0.973684atm × 14.3L )/T₂

14.21Latm / 293.15K = 13.92368Latm / T₂

14.21Latm × T₂ = 13.92368Latm × 293.15K

14.21Latm × T₂ = 4081.72679LatmK

T₂ = 4081.72679LatmK / 14.21Latm

T₂ = 287.24K

T₂ = 14.09°C

Therefore, the temperature of the wind as that decreases the volume and the pressure of the balloon to the given values is 14.09°C.

Learn more about the combined gas law here: brainly.com/question/25944795

#SPJ1

4 0
3 years ago
Nitric oxide is formed in automobile exhaust when nitrogen and oxygen in air react at high temperatures.N2(g) + O2(g) 2NO(g)The
yanalaym [24]

Answer : The correct option is, (E) 7.8 atm

Explanation :

The partial pressure of N_2 = 8.00 atm

The partial pressure of O_2 = 5.00 atm

K_p = 0.0025

The balanced equilibrium reaction is,

                               N_2(g)+O_2(g)\rightleftharpoons 2NO(g)

Initial pressure     8.00      5.00            0

At eqm.               (8.00-x) (5.00-x)        2x

The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{NO})^2}{(p_{N_2})(p_{O_2})}

Now put all the values in this expression, we get :

0.0025=\frac{(2x)^2}{(8.00-x)\times (5.00-x)}

By solving the terms, we get:

x=0.15atm

The equilibrium partial pressure of N_2 = (8.00 - x) = (8.00 - 0.15) = 7.8 atm

Therefore, the equilibrium partial pressure of N_2 is 7.8 atm.

3 0
4 years ago
Write a scientific explanation that answers the following question: How do you know scientifically that fat and soap are differe
Fantom [35]
Fat and soap are different substances. <span>One reason is that they have a different malleability. The Soap is very hard and sturdy. The fat is soft. Also, soap and fat are different because they had different smells. The soap had a refreshing smell and a soapy one and the fat smelled rubbery like Play-doh.  Another reason why fat and soap are different substances is that they don’t dissolve the same in water and oil. Soap is soluble in water and shortening is not soluble in water. Soap is not soluble in oil and shortening is soluble in oil. In the water shortening did not become cloudy but soap did. When placed in oil, the shortening disappeared completely, while soap did not change at all.The melting point of the fat was 57.6 we could not find the melting point of the soap. The soaps melting point is higher than the water's boiling point. A property is something that describes an object and does not change. For example, the soap is white, where the fat is off white. Color is a property. Fat and soap are also different because they have different densities. The soap sank but the fat floated. The density of fat is about .88 g/ml and the density of soap is about 1.18 g/ml. </span><span>Fat and soap are not the same substances one reason is they have different properties.Malleability, hardness, solubility, melting point,color, and density are all properties. </span>A property is a characteristic of a substance that does not change. Different substances have different properties.<span> If they had the same properties, they would be the same substance, but, since they don’t, they are different substances.

Hope this helps :D</span>
5 0
4 years ago
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