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3 years ago

32. A forest ranger. 35 meters above the ground in a

Physics

1 answer:

Sphinxa [80]3 years ago

8 0

Answer:

x = 102.33 m

Explanation:

Given that,

Position where a forest ranger stands is 35 m above the ground. The angle of depression to the base of the fire is 20. We need to find how far from the tower is the fire.

Let the distance is x. We can find x using trigonometry as follows :

$\sin\theta=\dfrac{\text{perpendicular}}{\text{hypotenuse}}\\\\\sin(20)=\dfrac{35}{x}\\\\x=\dfrac{35}{\sin(20)}\\\\x=102.33\ m$

Hence, the fire is at a distance of 102.33 m from the fire.

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What is the entire range of em waves called

Olin [163]

The entire range of anything is called its spectrum.

For em wavelengths, it's the electromagnetic spectrum.

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4 years ago

A baseball is thrown at an angle of 25 degrees relative to the ground at a speed of 23 m/s. If the ball was caught 42 m from the

ExtremeBDS [4]

Answer:

a) $v_{0y} = 9.72 m/s$

b) $v_{0x} = 20.85 m/s$

c) $t = 2.01 s$

d) $h_{max} = 4.82 m$

Explanation:

a) The initial vertical velocity is given by:

$v_{0y} = v*sin(\theta)$

Where:

θ: 25°

v: is the magnitude of the speed = 23 m/s

$v_{0y} = 23 m/s*sin(25) = 9.72 m/s$

b) The initial horizontal velocity can be calculated as follows:

$v_{0x} = v*cos(\theta) = 23 m/s*cos(25) = 20.85 m/s$

c) The flight time can be calculated using the following equation:

$v_{0x} = \frac{x}{t}$

Where:

x: is the total distance = 42 m

$t = \frac{x}{v_{0x}} = \frac{42 m}{20.85 m/s} = 2.01 s$

d) The maximum height is given by:

$v_{fy}^{2} = v_{0y}^{2} - 2gh_{max}$

Where:

$v_{fy}$ : is the final vertical velocity =0 (at the maximum heigth)

g: is the gravity = 9.81 m/s²

$h_{max} = \frac{v_{0y}^{2}}{2g} = \frac{(9.72 m/s)^{2}}{2*9.81 m/s^{2}} = 4.82 m$

I hope it helps you!

7 0

3 years ago

If the resistance through the fat is 3 times that through the muscle, how much of the total current goes through the fat in term

lapo4ka [179]

Answer:

it A i think

hope that helps if not i can change it

Explanation:

8 0

2 years ago

A 3-kg skateboard is rolling down the sidewalk at 4 m/s when it collides with a 1-kg skateboard that was initially at rest. If t

irga5000 [103]

Answer:

2 m/s

Explanation:

Parameters given:

Mass of first skateboard, m = 3 kg

Initial speed of first skateboard, u = 4 m/s

Mass of second skateboard, M = 1 kg

Initial speed of second skateboard, U = 0 m/s

Final speed of second skateboard, V = 6 m/s

Using the principle of the conservaton of momentum, the total initial momentum is equal to the total final momentum.

Momentum is the product of mass and velocity. This implies that:

m*u + M*U = m*v + M*V

(3*4) + (1*0) = (3*v) + (1*6)

12 + 0 = 3v + 6

=> 3v = 12 - 6

3v = 6

v = 6/3 = 2 m/s

The final speed of the 3 kg skateboard is 2 m/s

8 0

4 years ago

Read 2 more answers

A force of 100 N acts on a body and moves at a distance of 2 m in the direction of the force. How much work has been done?

Flauer [41]

Answer:

200 joules

Explanation:

work=force×distance

5 0

3 years ago