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Anna71 [15]
4 years ago
7

Please help I'm desperate. and please explain how need to show work!

Physics
1 answer:
ehidna [41]4 years ago
6 0

Answer:

33.2 m/s

Explanation:

In order to solve this problem, we need to know the mass of the car.

Here, we assume that the mass of the car is

m = 1 kg

Then, we can apply the work-energy theorem, which states that the work done on the car by the braking force is equal to the change in its kinetic energy:

W=\Delta E_k\\Fd=\frac{1}{2}mv^2-\frac{1}{2}mu^2

where:

F = -3.87 N is the force applied by the brakes (negative because its direction is opposite to the motion of the car)

d = 4.92 m is the displacement of the car

u = 33.8 m/s is the initial velocity of the car

v is the final velocity of the car

Therefore, solving for v, we find:

v=\sqrt{\frac{2Fd}{m}+u^2}=\sqrt{\frac{2(-3.87)(4.92)}{1}+(33.8)^2}=33.2 m/s

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Sawyer launches his 180 kg raft on the Mississippi River by pushing on it with a force of 75N. How long must Sawyer push on the
Daniel [21]

Answer: 4.8 s

Explanation:

We have the following data:

m=180 kg the mass of the raft

F=75 N the force applied by Sawyer

V=2 m/s the raft's final speed

V_{o}=0 m/s the raft's initial speed (assuming it starts from rest)

We have to find the time t

Well, according to Newton's second law of motion we have:

F=m.a (1)

Where a is the acceleration, which can be expressed as:

a=\frac{\Delta V}{\Delta t}=\frac{V-V_{o}}{t-t_{o}} (2)

Substituting (2) in (1):

F=m\frac{V-V_{o}}{t-t_{o}} (3)

Where t_{o}=0

Isolating t from (3):

t=\frac{m(V-V_{o})}{F} (4)

t=\frac{180 kg(2 m/s-0 m/s)}{75 N}

Finally:

t=4.8 s

6 0
3 years ago
QUICK!! What class of leer is shown below?
wlad13 [49]

Answer:

3rd class lever

HOPE IT HELPS YOU OUT PLEASE MARK IT AS BRAINLIEST AND FOLLOW ME PROMISE YOU TO FOLLOW BACK ON BRAINLY.IN

5 0
3 years ago
Read 2 more answers
A current I flows down a wire of radius a.
Helga [31]

Answer:

(a) K = \frac{I}{2\pi a}

(b) J = \frac{I}{2\pi as}

Explanation:

(a) The surface current density of a conductor is the current flowing per unit length of the conductor.

                                   K = \frac{dI}{dL}

Considering a wire, the current is uniformly distributed over the circumferenece of the wire.

                                   dL = 2\pi r

The radius of the wire = a

                                    dL = 2\pi a

The surface current density K = \frac{I}{2\pi a}

(b) The current density is inversely proportional

                                     J \alpha  s^{-1}    

                                     J = \frac{k}{s}           ......(1)

k is the constant of proportionality

                                     I = \int\limits {J} \, dS

                                     I = J \int\limits \, dS     ........(2)

substituting (1) into (2)

                                     I = \frac{k}{s} \int\limits\, dS

                                     I = k \int\limits^a_0 \frac{1}{s}  {s} \, dS

                                     I = 2\pi k\int\limits\, dS

                                     I = 2\pi ka

                                     k = \frac{I}{2\pi a}

substitute J = \frac{k}{s}

                                     J = \frac{I}{2\pi as}

7 0
3 years ago
If a metal has a mass of 78.2 g and a volume of 11.4 mL, what is its density?
hram777 [196]

Answer:

6.86g/mL

Explanation:

4 0
3 years ago
What is energy?
mestny [16]

Answer:

Energy is the ability for an object to do work.

Kinetic energy is energy which a body possesses while in motion.

Stored Energy = Potential Energy.

Speed is a measurement of how quickly something is able to move or operate.

6 0
3 years ago
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