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GuDViN [60]
3 years ago
5

Lance is 5 feet tall. His shadow is 8 feet long. At the same time of day trees shadow is 32 feet long. What is the height of the

tree in feet.
Mathematics
1 answer:
navik [9.2K]3 years ago
3 0

Set u a ratio of height over shadow:

Lance = 5 feet tall / 8 foot shadow

Tree = X feet tall / 32 foot shadow.

Set the ratios equal to each other and solve for X:

5/8 = x/32

Cross multiply:

8x = 160

Divide both sides by 8:

x = 160/8

x = 20

The tree is 20 feet tall.

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Match each expression to its equivalent standard form.
Aleksandr [31]

Let's expand the products they are all in the form

(a+b)(a-b)=a^2-b^2

For the first one we have a=x and b=2i:

(x+2i)(x-2i)=x^2-(2i)^2=x^2+4

For the second one we have a=x-2 and b=2i:

(x-2+2i)(x-2-2i)=(x-2)^2-(2i)^2 = x^2-4x+4+4=x^2-4x+8

For the third one we have a=x+1 and b=i:

(x+1+i)(x+1-i)=(x+1)^2-i^2=x^2+2x+1+1=x^2+2x+2

3 0
4 years ago
Amy jogs 1/3 of a mile in 1/15 of an hour, while john takes 1/30 of an hour to jog 1/5 of a mile. If they continue at this rate,
jolli1 [7]

Step-by-step explanation:

Given that,

Amy jogs 1/3 of a mile in 1/15 of an hour and john takes 1/30 of an hour to jog 1/5 of a mile.

Speed of Amy,

v_1=\dfrac{\dfrac{1}{3}\ miles }{\dfrac{1}{15}\ h}=5\ mph

Speed of John,

v_2=\dfrac{\dfrac{1}{5}\ miles }{\dfrac{1}{30}\ h}=6\ mph

John will jog farther in one hour as he is moving with faster speed. The speed of John is 1 mph more than Amy.

6 0
3 years ago
4 pounds of grapes cost $11.52. what is the unit rate?
Zepler [3.9K]

Answer: 2.88/1

Step-by-step explanation:

3 0
3 years ago
25x + 4x = x + 3x +7
Musya8 [376]

For this equation its the same as simplifying any other equation -Simplify both sides of the equation then isolate the variable- Easy then once you've do so the answer should be

<u>x = \frac{7}{26\\}</u>

7 0
3 years ago
Read 2 more answers
Given: 1; -5; -13 ; -23 ; ...<br><br> Derive a formula for the nth term in the pattern.
mylen [45]

Answer:

  f(n) = -n^2 -3n +5

Step-by-step explanation:

Suppose the formula is ...

  f(n) = an^2 +bn +c

Then we have ...

  f(1) = 1 = a(1^2) +b(1) +c

  f(2) = -5 = a(2^2) +b(2) +c

  f(3) = -13 = a(3^2) +b(3) +c

__

Here's a way to solve these equations.

Subtract the first equation from the second:

  -6 = 3a +b . . . . . 4th equation

Subtract the second equation from the third:

  -8 = 5a +b . . . . . 5th equation

Subtract the fourth equation from the fifth:

  -2 = 2a

  a = -1

Then substituting into the 4th equation to find b, we have ...

  -6 = 3(-1) +b

  -3 = b

and ...

  1 = -1 +(-3) +c . . . . . substituting "a" and "b" into the first equation

  5 = c

The formula is ...

  f(n) = -n^2 -3n +5

3 0
4 years ago
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