Here's a subtraction problem that has been solved incorrectly.

this is formula manipulation, I'd appreciate if the steps were provided. only respond if you know how to get the answer, thank y

marissa [1.9K]

Answer:

r = 3V/(2πh²)
h = 3V/b²
r = 25/π cm ≈ 7.9577 cm
w = 15 cm

Step-by-step explanation:

1. Multiply both sides of the equation by the reciprocal of the coefficient of r.

$V\cdot\dfrac{3}{2\pi h^2}=r\\\\r=\dfrac{3V}{2\pi h^2}$

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2. Multiply both sides of the equation by the reciprocal of the coefficient of h.

$V\cdot\dfrac{3}{b^2}=h\\\\h=\dfrac{3V}{b^2}$

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3. Solve the circumference formula for r, then substitute the given information.

$C=2\pi r\\\\r=\dfrac{C}{2\pi}\qquad\text{divide by the coefficient of r}\\\\r=\dfrac{50\,\text{cm}}{2\pi}=\dfrac{25}{\pi}\,\text{cm}\approx 7.9577\,\text{cm}$

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4. Solve the perimeter formula for width, the substitute the given information and do the arithmetic.

$P=2(L+W)\\\\\dfrac{P}{2}=L+W\qquad\text{divide by 2}\\\\\dfrac{P}{2}-L=W\qquad\text{subtract L}\\\\\dfrac{40\,\text{cm}}{2}-5\,\text{cm}=W=15\,\text{cm}$

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In general, solving for a particular variable involves "undoing" what has been done to the variable, usually in the reverse order. In part 4, the variable W has L added and the sum is multiplied by 2. We "undo" those operations, last operation first, by dividing by 2 and subtracting L.

The properties of equality say you can do what you like to an equation as long as you do the same thing to both sides of the equation. So, when we say "divide by 2", we mean "divide both sides of the equation by 2." Likewise, "subtract L" means "subtract L from both sides of the equation."

4 0

3 years ago

Simply 3x +9y + 2x Please help me

dem82 [27]

Answer:

5x+9y

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

1.

$m^{-1}=\dfrac{1}{m}$

2.

$q^0=1$

3.

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

4.

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

5.

$m^{-1}=\dfrac{1}{m}$

6.

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

7.

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

8.

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

3 years ago

I will give brainliest to whoever gets it right!!

const2013 [10]

Answer:

2/-3 is the answers for the question

Step-by-step explanation:

please give me brainlest to me please

6 0

3 years ago

Read 2 more answers

I think its C, not sure

Alona [7]

Yes; you are correct.
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The correct answer is:
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Answer choice: [C]: " x³ − 9x² + 23x − 12 " .
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Note: (a − b) (c − d + e) = ac − ad + ae − bc + bd − be ;
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(x − 4) (x² − 5x + 3) =

x * x² = x³ −

x * 5x = 5x² +

x * 3 = 3x −

4 * x² = 4x² −

-4 * 5x = -20x +

-4 * 3 = -12;
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 (x − 4) (x² − 5x + 3) =

x³ − 5x² + 3x −4x² − (-20x) + (-12) ;

= x³ − 5x² + 3x −4x² + 20x − 12 ;

= x³ − 5x² − 4x² + 3x + 20x − 12 ;

= x³ − 9x² + 23x − 12 ; which is:
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Answer choice: [C]: " x³ − 9x² + 23x − 12 " .
__________________________________________________

7 0

3 years ago