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lozanna [386]
3 years ago
6

Find the lateral area of the square pyramid shown, to the nearest whole number.

Mathematics
2 answers:
mylen [45]3 years ago
3 0
I believe the correct answer is D)
almond37 [142]3 years ago
3 0

Answer:

The correct answer is option D

Step-by-step explanation:

The lateral area of pyramid is

l * \sqrt{(w/2)^2 + h^2}  + w * \sqrt{(l/2)^2 + h^2} \\

Where

l = 42 yd\\w = 42 yd\\h = 38 yd\\

Substituting all these values in above equation, we get -

42 * \sqrt{(\frac{42}{2})^2 + 38^2 } \\ + 42 * \sqrt{(\frac{42}{2})^2 + 38^2 } \\\\= 2 * 42 * 43.41\\= 3647 yd^2\\

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Answer:

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Step-by-step explanation:

distance between 2 points (a,b) and (c,d) = \sqrt{(a^{2}-c^{2} ) +(b^{2}-d^{2} ) }

= \sqrt{((-8)^{2}-(-2)^{2} ) + ((-6)^{2}-4^{2})   }

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Answer:

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