Question

Find the lateral area of the square pyramid shown, to the nearest whole number.

Answer 1

I believe the correct answer is D)

Answer 2

Answer:

The correct answer is option D

Step-by-step explanation:

The lateral area of pyramid is

$l * \sqrt{(w/2)^2 + h^2} + w * \sqrt{(l/2)^2 + h^2}$

Where

$l = 42 yd\\w = 42 yd\\h = 38 yd$

Substituting all these values in above equation, we get -

$42 * \sqrt{(\frac{42}{2})^2 + 38^2 } \\ + 42 * \sqrt{(\frac{42}{2})^2 + 38^2 } \\\\= 2 * 42 * 43.41\\= 3647 yd^2$