Assuming we are solving for t
2<-1t
3
They have two different place values one 6 is in ten thousands place the other is in the hundred thousands place
The perimeter would be about 34.4 because if you choose the bottom side to be ten, by multiplying 35 by 2 to get 70 you can divide by 10 to get 7. Since you know the height and width, you can use pythagorean theorem, a^2 + b^2 = c^2. Plug in the numbers you have 10^2+7^2=c^2. c^2=149, so if you square root 149 you will get a irrational number but when rounded you get 12.2- so that is one side multiply by 2 and get 24.4- and add 10 to get 34.4
Option 3 should be correct. Use rise over run.
From the above definition, we can say that the cross-section, as a result of the plane intersecting the sphere through its centre, will be a circle with the radius "r" same as that of the given sphere. Thus, the area of the cross section is 15.2 m²
