The answer is Megan
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No.
Pi is an irrational number, because it keep repeating with no end. So 3π is irrational.
Answer:
There are three fourths in 3 fourths
Step-by-step explanation:
Fourth represents ![\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D)
Therefore, 3 fourths will be given as:
![3\times (\frac{1}{4}) = \frac{3}{4}](https://tex.z-dn.net/?f=3%5Ctimes%20%28%5Cfrac%7B1%7D%7B4%7D%29%20%3D%20%5Cfrac%7B3%7D%7B4%7D)
Therefore,
No. of fourths in 3 fourths = ![\frac{\frac{3}{4}}{\frac{1}{4}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B3%7D%7B4%7D%7D%7B%5Cfrac%7B1%7D%7B4%7D%7D)
No. of fourths in 3 fourths = ![\frac{3}{4}\times \frac{4}{1} = 3](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%5Ctimes%20%5Cfrac%7B4%7D%7B1%7D%20%3D%203)
Answer:
630>=210+5.25
Step-by-step explanation:
cant go over 630, so the symbol is >=
so...
630>=210+5.25
Its right, trust me
The value of x is ![\frac{8}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B3%7D)
Explanation:
The expression is
Adding
to both sides of the equation, we get,
![\log _{2}(9 x)=3+\log _{2}(3)](https://tex.z-dn.net/?f=%5Clog%20_%7B2%7D%289%20x%29%3D3%2B%5Clog%20_%7B2%7D%283%29)
Using log definition, if
then
, we have,
![9 x=2^{3+\log _{2}(3)}](https://tex.z-dn.net/?f=9%20x%3D2%5E%7B3%2B%5Clog%20_%7B2%7D%283%29%7D)
Using exponent rule,
,
![9x=2^{\log _{2}(3)} \cdot 2^{3}](https://tex.z-dn.net/?f=9x%3D2%5E%7B%5Clog%20_%7B2%7D%283%29%7D%20%5Ccdot%202%5E%7B3%7D)
Simplifying, we have,
![9x=3\cdot8\\9x=24](https://tex.z-dn.net/?f=9x%3D3%5Ccdot8%5C%5C9x%3D24)
Dividing both sides by 9, we have,
![x=\frac{24}{9}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B24%7D%7B9%7D)
Simplifying,
![x=\frac{8}{3}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B8%7D%7B3%7D)
Thus, the value of x is ![\frac{8}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B3%7D)