To solve this problem you must apply the proccedure shown below:
1. You have the following equation of a parabola, given in the problem above:
x<span>=1/16y^2
2. Then, based on the graph attached, you have:
p=y^2/4x
p=8^2/(4)(4)
p=64/16
p=4
3. The directrix is:
directrix=h-p
directrix=0-4
directrix=-4
The answer is:-4</span>
Answer:
235
Step-by-step explanation:
42+1
43
3 times 43
129
129 times 2
258
258-23
235
Answer:
x = 6
y = -2
Step-by-step explanation:
6 - 8 = -2
2 x 6 = 12 - 14 = -2
Since you haven't identified this figure, I'm going to assume that it's a rectangle.
The Perimeter of a rectangle of length L and width W is P = 2L + 2W.
Here you are given the Perimeter and the length, and are to find the width, W.
Solving the above equation for W, we get P - 2L = 2W.
Dividing by 2 (to isolate that W), we get
P
-- - L = W
2
Substitute P= 6 yds and L = 6 feet (or 2 yds), find W (in yards).
Answer:
A
Step-by-step explanation:
x=6.28111...
100 x=628.111...
1000x=6281.111...
subtract
900x=5653
x=5653/900
density of iodine=785×5653/900≈4930.672222...
Here 2 is repeating .