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Mars2501 [29]
4 years ago
10

0.9 < -r plz help thank you

Mathematics
1 answer:
Komok [63]4 years ago
3 0
0.9 will equal to \frac{9}{10}

Anyhow ! Lets get to the steps!

\frac{9}{10} - r  \leq  ?

\frac{9}{10}

Now "r" will become a negative 

\frac{9}{10} - - r  \leq ?

\frac{-r(10)}{10}

\frac{10(r)+9}{10}  \leq 0

 We have to multiply from each of your sides by the number 10

You  can even divide by the number 10 aswell

Back to the steps

r+ \frac{9}{10}  \leq  ?

Subtract from this fraction \frac{9}{10} to your sides 

This would be inequality r + .900  \leq ?

r \ \textless \   -\frac{9}{10} ← this should most likely be your answer 

Now, Good Luck



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I need help for #1 (an explanation would be great too).
Ivan

Answer:

±6i√2

Step-by-step explanation:

Recall that the square root of a negative number is imaginary, which is shown by the use of "i."

Examples:  √4 = ±2; √4 = i√4 = ±i2

Then √72 = ±√36√2 = ±6√2, and

   

      √(-72) = ± i√36√2 = ±6i√2

         

Note that this is identical to the result shown in the problem:  √(36·2·(-1) )

5 0
3 years ago
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Answer:

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.,..................................
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