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DerKrebs [107]
2 years ago
12

Newton's second law is F = ma. In this task, you will plan two controlled experiments to see how changes in force and changes in

mass affect the motion of the box in the hanging weight simulation from task 1. Because you don’t have access to special measuring devices, you’ll just use observation to compare the acceleration of the box as it moves across the table. You should change only the force or the mass, but not both, because these are controlled experiments.
estimated time to complete: 20 minutes

Part A
Plan a controlled experiment that uses the simulation to investigate how changing the mass of an object changes its acceleration. The net force on the object must stay the same. Record your plan here.
Mathematics
1 answer:
Katarina [22]2 years ago
5 0
Joe mama 919229922929922929292
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Sixty photos taken at a photo shoot are in black and white. If this represents 15 percent of the total number of photos taken, w
Art [367]

Answer:

D. 15×4/100×4 = 60/400

Step-by-step explanation:

First I figured out how many photos there are in total, which was by doing 60/.15, since only 15% of the total photos are in black and white. We can already cross out all possibilities that don't have the denominator 400, but we can go a step further by seeing which one is 60/400, or equal to 60/400, which is D. 15×4/100×4 = 60/400.

7 0
2 years ago
Which is an equation of a circle with center (-10, 6) and radius 8?
kupik [55]
An equation of a circle:

(x - a)² + (y - b)² = r²

(a; b) - a coordinates of a center
r - a radius

r = 8; (-10; 6) ⇒ a = -10 and b = 6

subtitute

(x - (-10))² + (y - 6)² = 8²

Answer: (x + 10)² + (y - 6)² = 64
8 0
3 years ago
77 7/8% into a fraction
wariber [46]
The answer is 623/800 and that is in simplest form.
3 0
2 years ago
HELP PLZ WILL GIVE BRAINLIEST! find the arrithmetic means in the given sequence<br> -3,?,?,?,93
pav-90 [236]

Answer:

Step-by-step explanation:

The standard form of an arithmetic sequence is

aₙ = a₁ + d(n - 1)

where aₙ is the number of the term in the sequence (in order from first term where n = 1, to second term where n = 2, to third term where n = 3, etc) a₁ is the the first term in the sequence, and d is the arithmetic difference or means.  This is what we are looking to solve for.  

In our sequence we have the first term, -3 (where n = 1) and the fifth term, 93 (where n = 5).  If we fill in what we have, the only unknown is d, our arithmetic difference (means) between each number in the sequence.

Because we have the fifth term, we can write our standard form to fit our needs:

a₅ = a₁ + d(n-1).  Therefore,

93 = -3 + d(5 - 1) and

93 = -3 + d(4) so

96 = 4d and

d = 24

Our arithmetic difference (means) is 24.  Let's test it on a few values of n.  Let's look for the second, third, and 4th terms, and then try it out for n = 5 to make sure the 5th term, using our arithmetic sequence with d = 24 works and we do, in fact, find the fifth term to be 93.

Testing n = 2

a₂ = -3 + 24(2 - 1) so

a₂ = -3 + 24(1)  and

a₂ = 21.  Second term is 21 (Notice that difference between -3 and 21 is 24)

Testing n = 3

a₃ = -3 + 24(3 - 1) so

a₃ = -3 + 24(2) and

a₃ = 48 - 3 and

a₃ = 45 (Notice the difference between 21 and 45 is 24)

Testing n = 4

a₄ = -3 + 24(4 - 1) so

a₄ = -3 + 24(3) and

a₄ = 72 - 3 and

a₄ = 69 (Notice the difference between 45 and 69 is 24)

Testing n = 5 (and it better come out as 93 or we did something wrong!)

a₅ = -3 + 24(5 - 1) and

a₅ = -3 + 24(4) so

a₅ = 96 - 3 so

a₅ = 93 (Phew!)  ; )

5 0
3 years ago
Read 2 more answers
Can someone plz help me with this!
asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

2x+y=10\\x-3y=-2

To solve, start by isolating your first equation for y.

2x+y=10\\y=-2x+10

Now, plug this value of y into your second equation.

x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4

System #2: x=1

x+2y=5\\2x+y=4

Isolate your second equation for y.

2x+y=4\\y=-2x+4

Plug this value of y into your first equation.

x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1

System #3: x=6

5x+y=33\\x=18-4y

Isolate your first equation for y.

5x+y=33\\y=-5x+33

Plug this value of y into your second equation.

x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6

System #4: all real numbers (not included in your diagram)

y=13-2x\\8x+4y=52

Plug your value of y into your second equation.

8x+4(13-2x)=52\\8x+52-8x=52\\0=0

<em>all real numbers are solutions</em>

System #5: x=2

x+3y=5\\6x-y=11

Isolate your second equation for y.

6x-y=11\\-y=-6x+11\\y=6x-11

Plug in your value of y to your first equation.

x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2

System #6: no solution (not included in your diagram)

2x+y=10\\-6x-3y=-2

Isolate your first equation for y.

2x+y=10\\y=-2x+10

Plug your value of y into your second equation.

-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2

<em>no solution</em>

System #7: x=3

y=10+x\\2x+3y=45

Plug your value of y into your second equation.

2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3

3 0
2 years ago
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