The winning times (in seconds) in a speed-skating event for men can be represented by the formula T = 46.12 - 0.094x where x rep

Question

3 years ago

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The winning times (in seconds) in a speed-skating event for men can be represented by the formula T = 46.12 - 0.094x where x rep

resents the year, with x=0 corresponding to 1920. (For example in 1992, x would be 1992 - 1920 = 72.) According to the formula, what was the winning time in 1983? Round to the nearest hundredth.

Mathematics

1 answer:

Nostrana [21] · Answer 1 · 2022-02-12T13:53:38+03:00

Nostrana [21]3 years ago

6 0

The given question is:

The winning times (in seconds) in a speed-skating event for men can be represented by the formula T = 46.12 - 0.094x where x represents the year, with x=0 corresponding to 1920.

In 1983,

$x = 1983 -1920 = 63$

Substituting 63 for x in the given equation, we will get

$T = 46.12 -0.094(63) =40.198= 40.20$