Answer:
Year 7 = 75 students
Year 9 = 25 students
Step-by-step explanation:
Year 7 has 3/8 of the total since the circle is divided into 8 sections and has 3 of the 8 sections
3/8 * 200 students = 75
Year 9 has 1/8 of the total since the circle is divided into 8 sections and has 1 of the 8 sections
1/8 * 200 =25
X=2
-- ---
5 3
Cross multiply:
3x=10
x=10/3
2=5
-- ---
3 y
2y=15
y=15/2
10/3=15/2 :)
Answer:
<em>Hello your question is incomplete attached below is the complete question</em>
answer : There is not convincing statistical evidence to suggest that the proportion of customers who order dessert at each restaurant is not the same based on family classification. ( E )
Step-by-step explanation:
To arrive at this conclusion we will determine the Null and alternate hypothesis
<em>H0 : Number that orders dessert is same based on family classification given</em>
<em>Ha : Number that orders dessert is not the same based on family classification given </em>
from the question the p-value of Chi-square test is 0.092 > 0.05 hence we will fail to reject the null hypothesis. therefore we can conclude that
There is not convincing statistical evidence to suggest that the proportion of customers who order dessert at each restaurant is not the same based on family classification
Answer
8x^3 - 6x^4 + 12x^3
<span>1. a sine curve with amplitude 2, and period 4pi radians
</span>
the general equation of the sine curve ⇒⇒ y = a sin (nθ)
where: a is the amplitude and n = 2π/perid
∵ <span>amplitude 2, and period 4pi radians
</span>
∴ y = 2 sin (θ/2)
The correct answer is option D. y = 2 sin (θ/2)
===========================================
<span>2.The period and amplitude of the function ⇒⇒ y = 5 cos 2θ
</span>
<span>comparing with y = a cos nθ
</span>
where : a is the amplitude and n = 2π/period
<span>amplitude = 5 , period = 2π/n = 2π/2 = π
</span>
The correct answer is option B. Period: pi radians: Amplitude:5
============================================================
3. tan (2π/3) = tan 120° = -√3
120° lie in the second quadrant and its reference angle = 180° - 120° = 60°
tan function in the second quadrant is negative
∴ tan 120° = - tan 60 = -√3
The correct answer is C. -sqrt3
=====================================================
4. <span>Tan 5π/6 = tan 150° = -(√3)/3
</span>
150° lies in the second quadrant and its reference angle = 180° - 150° = 30°
tan function in the second quadrant is negative
∴ tan 150° = - tan 30 = -(√3)/3
The correct answer is <span>B.-sqrt3/3</span>
