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lisov135 [29]
3 years ago
6

The district manager of four different restaurants wanted to investigate whether the four restaurants differed with respect to c

ustomers ordering dessert or not based on family classification (with children or without children). Independent random samples of 100 customers who ordered dessert were selected from each restaurant, and the customers were identified as either being with children or without children. After verifying the conditions for the appropriate hypothesis test, the manager calculated a chi-square test statistic of 6.45 with an associated
Mathematics
1 answer:
Alex_Xolod [135]3 years ago
5 0

Answer:

<em>Hello your question is incomplete attached below is the complete question</em>

answer : There is not convincing statistical evidence to suggest that the proportion of customers who order dessert at each restaurant is not the same based on family classification. ( E )

Step-by-step explanation:

To arrive at this conclusion we will determine the Null and alternate hypothesis

<em>H0 : Number that orders dessert is same based on family classification given</em>

<em>Ha : Number that orders dessert is not the same based on family classification given </em>

from the question the p-value of Chi-square test is 0.092 > 0.05 hence we will fail to reject the null hypothesis. therefore we can conclude that

There is not convincing statistical evidence to suggest that the proportion of customers who order dessert at each restaurant is not the same based on family classification

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The perimeter of a rectangular park is 500 feet. The length of the park is 100 feet longer than the width. Find the length of th
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Answer:

The length of the park is 175 feet

Step-by-step explanation:

Let us solve the question

∵ The perimeter of a rectangular park is 500 feet

∵ The formula of the perimeter of the rectangle is P = 2(L + W)

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→ Equate the rule of the perimeter by 500

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→ Divide both sides by 2

∴ L + W = 250 ⇒ (1)

∵ The length of the park is 100 feet longer than the width

→ That means L is W plus 100

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→ Substitute L in (1) by (2)

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→ Add the like terms

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