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jolli1 [7]
3 years ago
11

A wire having a mass per unit length of 0.440 g/cm carries a 1.50-A current horizontally to the south. (a) What is the direction

of the minimum magnetic field needed to lift this wire vertically upward?
Business
1 answer:
coldgirl [10]3 years ago
4 0

Answer:

B = 0.287  Tesla

According to thumb rule the direction of magnet is to the east.

Explanation:

F = BiL sin∅

note that F = mg

B = magnetic field

i = current

therefore,

mg = BiLsin∅

Make B subject of the formula

B = mg/iLsin∅

m/L = mass per length of the wire and it is given in gram per centimeter . It should be converted to kg per meter.

m/L = 0.440 g/cm

convert to kg/m = 0.440 × 0.001 kg × 100 m = 0.044  kg/m

B = 9.8 × 0.044 / sin 90 × 1.50 × 1

B = 0.4312/ 1.50

B = 0.28746666666

B = 0.287  Tesla

According to thumb rule the direction of magnet is to the east.

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Demand pull inflation can be started by A. an increase in the price of oil B. a decrease in the quantity of money. C. an increas
devlian [24]

Answer:

Option "C" is correct.

Explanation:

An increase in government expenditure causes more money inflow on demand over supply.

6 0
3 years ago
ECG Company recorded two sales on March 1 of $20,000 and $30,000 under credit terms of 3/10, n/30 (3% discount if paid within 10
AlladinOne [14]

Answer:

In net method the discount not given is recorded as revenue and in gross method the discount allowed is recorded as expense.

Explanation:

ECG Company

Journal Entries

<u>Net  Method</u>

Date               Particulars                         Debit             Credit

1 March        Accounts Receivable       19400

                     Accounts Receivable     29,100

                              Sales                                              48500

( Calculation of net Sales ( 20,000* 3% = 600, 30,000* 3%= 900) 20,000- 600= 19,400 and 30,000- 900= 29,100)

8 Mar             Cash                         19400

                          Accounts Receivable                      19400

Receipt of 20,000 Sales within discount period.

25 Mar          Cash                        30,000

                      Accounts Receivable                          29,100

                    Interest Revenue                                        900

Receipt of payment after discount time period.

<u>Gross Method</u>

1 March        Accounts Receivable       20,000 Dr

                     Accounts Receivable      30,000 Dr

                              Sales                                              50,000 Cr

Transactions of Sales on gross method. Here discount is not calculated unless given.

8 Mar             Cash                         19400 Dr

                      Discount Allowed       600 Dr

                          Accounts Receivable                      20,000 Cr

Receipt of 20,000 Sales within discount period.

25 Mar          Cash                        30,000 Cr

                      Accounts Receivable                          30,000 Cr

           Receipt of Sales of 30,000 after the discount period.

6 0
3 years ago
Compute the payback period for each of these two separate investments:
Gnesinka [82]

Answer:

A. 1.89 years

B. 2.33 years

Explanation:

According to the scenario, computation of the given data are as follows,

(A) After-tax income = $72,115

Expected cost = $250,000

Useful life = 4 years

Salvage value = $10,000

Depreciation Value = ($250,000 - $10,000) ÷ 4 = $60,000

Annual net cashflow = After tax income + Depreciation

= $72,115 + $60,000 = $132,115

Payback Period = Machine expected cost ÷ Annual net cash flow

= $250,000 ÷ $132,115

= 1.89 years

(B) After-tax income = $39,000

Machine cost = $200,000

Useful life = 8 years

Salvage value = $13,000

Depreciation value = ($200,000 - $13,000) ÷ 4 = $46,750

Annual net cashflow = After tax income + Depreciation

= $39,000 + $46,750 = $85,750

Payback Period = Machine expected cost ÷ Annual net cash flow

= $200,000 ÷ $85,750

= 2.33 years

4 0
2 years ago
Kirkaid Company recorded the following transactions for the just completed month:
Illusion [34]

Answer:

The correct answer is $5,000.

Explanation:

According to the scenario, the given data are as follows:

Total raw material = $118,000

Direct material = $89,000

So, Indirect material = Total raw material - Direct material = $118,000 - $89,000

= $29,000

Total labor = $142,000

Direct labor = $122,000

So, Indirect labor = Total labor - Direct labor = $142,000 - $122,000

= $20,000

Additional actual manufacturing OH = $214,000

Applied manufacturing OH = $268,000

So, we can calculate the underapplied or overapplied overhead for the month by using following formula:

Underapplied or overapplied overhead = Applied manufacturing OH - Actual OH

= $268,000 - ( $29,000 + $20,000 + $214,000)

= $268,000 - $263,000

= $5,000

Hence, the overapplied overhead is $5,000.

6 0
3 years ago
Eileen transfers property worth $200,000, basis of $60,000, to Goldfinch Corporation. In return, she receives 82% of the stock i
erica [24]

Answer:

C. $20,000

Explanation:

Given the data below,

Property transfered = $200,000

Basis = $60,000

Return = 82℅

Fair market value = $180,000

Long term fair market value = $20,000

In the above scenario, we can safely say that Eileen realized gain of $140,000 on the transfer of property, which is due to;

Property worth $200,000 - basis $60,000 = $140,000.

However, because recognized gain cannot exceed the lesser of realized gain ($140,000) or the boot received ($20,000), the recognized gain is therefore $20,000

3 0
3 years ago
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