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Aneli [31]
3 years ago
12

Consider the following statements about crystalline solids:

Chemistry
2 answers:
Gnom [1K]3 years ago
8 0

Answer:

(iii) Ionic solids have formula units in the point of the crystal lattice

Explanation:

To further clarify, ionic solids exists as crystal lattice in which each ion is bonded by electrostatic attraction or force to multiple neighboring ions with same or opposite charge thereby balances the force holding them together.

Consider Sodium Chloride (Nacl) as an example, the positive charge of Na+ is bonded by electrostatic attraction to the negative charge of cl-

Natali5045456 [20]3 years ago
6 0

Answer:

Statements (iii) is false

Explanation:

Ionic solids do not have formula units in the points of the crystal lattice, instead, they have ions in the points of the lattice.

Consider the example of NaCl. Here Na⁺ is the cation while Cl⁻ is the anion, together they form a cubic unit cell by the electrostatic attraction between them. A crystal lattice defines the arrangement of atoms or molecules in a crystal, and the points on it represent the species which are responsible for the ordered arrangement. In the case of ionic solids, these species are ions, as they are responsible for electrostatic attraction or repulsion causing an ordered arrangement around it.

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What we call "tin cans" are really iron cans coated with a thin layer of tin. The anode is a bar of tin and the cathode is the i
UNO [17]

Answer:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

Explanation:

Although the context is not clear, let's look at the oxidation and reduction processes that will take place in a Fe/Sn system.

The problem states that anode is a bar of thin. Anode is where the process of oxidation takes place. According to the abbreviation 'OILRIG', oxidation is loss, reduction is gain. Since oxidation occurs at anode, this is where loss of electrons takes place. That said, tin loses electrons to become tin cation:

Sn (s)\rightarrow Sn^{2+} (aq) + 2e^-

Similarly, iron is cathode. Cathode is where reduction takes place. Reduction is gain of electrons, this means iron cations gain electrons and produce iron metal:

Fe^{2+} (aq) + 2e^-\rightarrow Fe (s)

The net equation is then:

Sn (s) + Fe^{2+} (aq)\rightarrow Fe (s) + Sn^{2+} (aq)

However, this is not the case, as this is not a spontaneous reaction, as iron metal is more reactive than tin metal, and this is how the coating takes place. This implies that actually anode is iron and cathode is tin:

Actual anode half-equation:

Fe (s)\rightarrow Fe^{2+} (aq) + 2e^-

Actual cathode half-equation:

Sn^{2+} (aq) + 2e^-\rightarrow Sn (s)

Actual net reaction:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

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3 years ago
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4 years ago
a student adds 3.5 moles of solute to enough water to make a 1500mL solution. what is the concentration?
aksik [14]
<h2>Hello!</h2>

The answer is:

MolarConcentration=\frac{3.5moles}{volume(1.5L)}=2.33molar

<h2>Why?</h2>

Since there is not information about the solute but only its mass, we need to assume that we are calculating the molar concentration of a solution or molarity. So, need to use the following formula:

MolarConcentration=\frac{mass(solute)}{volume(solution)}

Now, we know that the mass of the solute is equal  3.5 moles and the volume is equal to 1500 mL or 1.5L

Then, substituting into the equation, we have:

MolarConcentration=\frac{3.5moles}{1.5L}=2.33molar

Have a nice day!

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