Explanation:
The given data is as follows.
Mass of apple sauce mixture = 454 kg
Heat added (Q) = 121300 kJ
Heat capacity (
) of apple sauce at
= 4.0177
So, Heat given by heat exchanger = heat taken by apple sauce
Q = 
or, Q =
Putting the given values into the above formula as follows.
Q =
121300 kJ = 
= 
Thus, we can conclude that outlet temperature of the apple sauce is
.
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Exocytosis : exo- means outside , -cyte means cell
Answer is: .408,5 J.m(C₆H₆-benzene) = 39 g.
n(C₆H₆) = m(C₆H₆) / M(C₆H₆) = 39g ÷ 78g/mol = 0,5 mol.ΔT = 10,0°C, difference at temperature.c(benzene) = 81,7 J/mol·°C, specific heat of benzene.Q = n(benzene) · ΔT · c(benzene), heat of reaction.Q = 0,5 mol · 10,0°C · 81,7 J/mol·°C.Q = 408,5 J.