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trasher [3.6K]
3 years ago
14

1)The chemical properties of a compound are different from the chemical properties of a mixture because:

Chemistry
2 answers:
Liono4ka [1.6K]3 years ago
6 0
Here are the following solutions:

1. A
2. F
3. B.
Verdich [7]3 years ago
5 0

Answer:

1: A

2: False

3: D

Explanation:

1: There are many differences between compounds and mixtures. In compounds, the atoms are chemically bonded to each other, whereas in mixtures, they are not (there may be hydrogen bonds that form between the substances in the mixture, but those bonds are not strong enough to bind them irreversibly).

2: This statement is false because, this is proof of diffusion between the molecules, and not a chemical reaction. A chemical reaction can result in a colour change, however, not all colour changes are chemical reactions.

3: The reason the answer is D, is because that is the main difference between liquids and gasses. Both liquids and gasses can take the shape of the container they occupy (in the case of gasses, in a closed container, the gas will fill the container it occupies completely). Liquids and gasses both have no regular arrangement, and so this cannot be used as a difference between them. When a liquid turns into a gas, the bonds between the atoms get weaker, hence why the answer is D.

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if 3.0 grams of aluminum and 6.0 grams of bromine react to form AlBr3, how many grams of product would theoretically be produced
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1) Chemical reaction: 2Al + 3Br₂ → 2AlBr₃.
m(Al) = 3,0 g.
m(Br₂) = 6,0 g.
n(Al) = m(Al) ÷ M(Al).
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n(Al) = 0,11 mol.
n(Br₂) = n(Br₂) ÷ m(Br₂).
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m(AlBr₃) = 0,025 mol · 266,7 g/mol.
m(AlBr₃) = 6,67 g.

2) m(Br₂) - all bromine reacts, so mass of bromine after reaction is zero grams (m(Br₂) = 0 g).
n(Al) = 0,11 mol - 0,025 mol = 0,085 mol.
m(Al) = 0,085 mol · 27 g/mol.
m(Al) = 2,295 g.
m(AlBr₃) = 6,67 g · 0,72 (yield of reaction).
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n - amount of substance.
M - molar mass.

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