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PtichkaEL [24]
3 years ago
10

Use expanded form to help. 5×479=

Mathematics
2 answers:
Strike441 [17]3 years ago
3 0
5x479
2395x esta me dio la respuesta
Kitty [74]3 years ago
3 0
Five × Four hundred seventy nine
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The amount of money spent on textbooks per year for students is approximately normal.
Ostrovityanka [42]

Answer:a

a

   336.04    <  \mu < 443.96

b

  The  margin of error will increase

c

The  margin of error will decreases

d

The 99% confidence interval is  0.4107 <  p  < 0.4293

Step-by-step explanation:

From the question we are  told that

   The sample size  n =  19

    The sample mean is  \= x  = \$\  390

    The  standard deviation is  \sigma =  \$ \  120

 

Given that the confidence level is  95% then the level of significance is mathematically represented as

           \alpha = 100 -  95

          \alpha  =  5 \%

          \alpha  =  0.05

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table

    So  

         Z_{\frac{\alpha }{2} } =  1.96

The  margin of error is mathematically represented as

      E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

=>    E = 1.96 *  \frac{120}{\sqrt{19} }

=>   E = 53.96

The 95% confidence interval is  

     \= x  -  E  <  \mu < \= x  +  E

=>   390  -   53.96   <  \mu < 390  -   53.96

=>  336.04    <  \mu < 443.96

When the confidence level increases the Z_{\frac{\alpha }{2} } also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

         n  \  \ \alpha  \ \  \frac{1}{E^2 }

So if the sample size increases the margin of error decrease

The  sample proportion is mathematically represented as

       \r p  =  \frac{210}{500}

       \r p  = 0.42

Given that the confidence level is 0.99 the level of significance is  \alpha =  0.01

The critical value of \frac{\alpha }{2} from the normal distribution table is  

      Z_{\frac{\alpha }{2} }  =  2.58

  Generally the margin of error is mathematically represented as

       E =  Z_{\frac{\alpha }{2} }*  \sqrt{ \frac{\r p (1- \r p )}{n} }

=>   E =  0.42 *  \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }

=>     E =  0.0093

The 99% confidence interval  is

     \r p  -  E <  p  < \r p  +  E

     0.42  -  0.0093 <  p  < 0.42  +  0.0093

     0.4107 <  p  < 0.4293

 

4 0
4 years ago
What is the solution to the inequality x+(7+2x)≤−3x?
3241004551 [841]

Answer:

don't press that link

Step-by-step explanation:

8 0
3 years ago
The temperature, T , of a given mass of gas varies inversely with its volume, V . The temperature of a certain gas with volume o
alekssr [168]
We know that

if t<span>he temperature T of a given mass of gas varies inversely with its volume V 
</span>then
T=k/V

Step 1
Find the value of k
for T=30º C and V=105 cm³
we have 
T=k/V--------> k=T*V--------> k=30*105=3150 °C*cm³

therefore
for V=84 cm³
T=3150/84=37.5 °C

the answer is 37.5 °C
3 0
3 years ago
Min Jee wants to build a small patio using either brick or paver stones. It will be 70 inches long and 49 inches wide. Each bric
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brainly.com/question/283608 the answer is here and all the work too
4 0
3 years ago
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A toy company has determined that the revenue generated by a particular toy is modeled by the following equation:
Artemon [7]
R(x) = 11x - 0.025x^2
Revenue is maximum when dr(x)/dx = 0
dr(x)/dx = 11 - 0.05x = 0
0.05x = 11
x = 11/0.05 = 220
The revenue will be maximum when 220000 toys are produced.

r(220) = 11(220) - 0.025(220)^2 = 2,420 - 1,210 = 1,210
Therefore, maximum revenue = $1210000
8 0
3 years ago
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