15 mi/h= 15mi/60 min= 1/4 (mi/min)
x is original speed (mi/min)
t is original time
x*t =260
(x+1/4)=5x/4 is new speed
t-20 - new time
(x+1/4)(t-20)=260
xt = (x+1/4)(t-20)
xt=xt + t/4 - 20x - 5
t/4=20x+5
t=80x +20
We can substitute t=80x +20 into equation x*t =260
x*(80x+20)=260
80x²+20x-260=0
4x²+x-13=0
D=b² - 4ac = 1+4*4*13= 209
x=(-1+/-√209)/2*4
x=1.68 mi/min
1.68mi/min * 60 min/1h≈100 mi/h
Check
260/100=2.6h time with old speed
260/(115)=2.26 h time with new speed
2.6-2.26 = 0.34 h difference between old and new time
0.34h*60min/1h≈20 min difference between old and new time in minutes
Answer:
speed=24km/h or 6.67m/s
Step-by-step explanation:
Given data:
time taken = t =43 hours
distance covered = d = 1032 km
to find:
speed of the ship = v =?
solution:
as we know that speed is defined as the distance covered by an object in unit time.Formula
speed = distance covered /time taken
speed = 1032km/43hours
speed =24km/h or in international system of units the answer is 6.67m/s
Answer: 4
Step-by-step explanation:
The solution to the problem is as follows:
<span>ln(0.5) could be written as ln(2) - ln(2) - ln(2) = a - a - a = -a
</span>
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