Question

Determine the volume (in ml) of a 3.57 M solution of Zi Bry that contains 0.884 moles of ZnBr2

Answer 1

Answer:

The  volume (in ml) of a 3.57 M solution of $ZnBr_2$ that contains 0.884 moles of  $ZnBr_2$ is 247.61g mL

Explanation:

According to the definition of Molarity

which sates

"The amount of moles of a substance present in one litre of the solution is called as Molarity."

3.57M $ZnBr_2$ solution implies that 1000 mL of the solution conatins 3.57Moles of $ZnBr_2$

Hence , 3.57 moles of $ZnBr_2$ is present in the 1000 ml of solution

Now,

In 1 mole of $ZnBr_2$ is  present in the =$\frac{1000}{3.57}$ml of solution

Similarily ,

In 0.884  moles of$ZnBr_2$ is  present in the $\frac{1000\times 0.884}{3.57}$ of solution= 247.61g mL