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ASHA 777 [7]
3 years ago
9

A container of compressed hydrogen with a fixed volume has a pressure of 13.0 atm at a temperature of 20.0 °C. If its temperatur

e shoots up to 102 °C, what will the pressure be? A. 2.55 atm B. 10.2 atm C. 16.6 atm D. 66.3 atm
Chemistry
1 answer:
nevsk [136]3 years ago
8 0

Answer:

P₂ = 16.6 atm

Explanation:

Given data:

Initial pressure = 13.0 atm

Initial temperature = 20.0°C (20+273 = 293 K)

Final temperature = 102.0°C (102+273 =375 K)

Final pressure = ?

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

13.0 atm / 293 K =  P₂/375 K

P₂ = 13.0 atm × 375 K / 293 K

P₂ = 4875 atm. K /293 K

P₂ = 16.6 atm

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A sample of gas is inside of a rigid container with fixed volume of 350mL. The initial pressure of the system is 366kPa, and the
Cerrena [4.2K]

Answer:

457.5kPa

Explanation:

Given data

V1=V2=350mL  (<em>fixed volume</em> )

P1=366kPa

T1= 88 degrees Celsius

P2=??

T2= 110 degrees Celsius

For the general gas equation

P1V1/T1= P2V2/T2

V1=V2

P1/T1= P2/T2

Substitute

366/88= P2/110

Cross multiply we have

P2*88=366*110

P2*88= 40260

P2= 40260/88

P2= 457.5 kPa

Hence the pressure will change to 457.5kPa

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3 years ago
What is percent of C in CO2 (C=12.01 amu, O=16.00 amu)
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7 0
4 years ago
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. The density of gold is 19.32 g/mL. A U.S. $5.00 gold coin has a diameter of 1.62 cm and a thickness of 0.085 cm. The price of
Lostsunrise [7]

Answer:

$182 is the value of the gold in the coin

Explanation:

Diameter is 2r, the ratio of the coin is = 1.62cm / 2 = 0.81cm

Following the formula of the volume of the coin:

V = π r² h

V = π*(0.81cm)²*0.085cm

V = 0.172cm³ = mL

As the density of the gold is 19.32g/mL, the mass of 0.1752mL of gold is:

0.1752mL * (19.32g / mL) =

3.385g is the mass of the coin

As the price of the gold is $53.90 / g, the value of the gold in the coin is:

3.385g * ($53.90 / g) =

<h3>$182 is the value of the gold in the coin</h3>

7 0
3 years ago
Calculate the number of moles of Li3PO4 in 2.2 L of a 0.60 M Li3PO4 solution.
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Answer:

1.32 mole

Explanation:

The following data were obtained from the question:

Volume of solution = 2.2L

Molarity of solution = 0.60M

Mole of Li3PO4 =..?

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is represented as:

Molarity = mole /Volume

With the above formula we can easily calculate the number of mole of Li3PO4 as shown below:

Molarity =mole /Volume

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Cross multiply

Mole of Li3PO4 = 0.6 x 2.2

Mole of Li3PO4 = 1.32 mole

Therefore, 1.32 mole of Li3PO4 is contained in the solution.

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3 years ago
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