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ruslelena [56]
3 years ago
5

Ammonia is produced synthetically by the reaction: 2Fe+3Cl2 --- 2FeCl3

Chemistry
1 answer:
AlladinOne [14]3 years ago
5 0

Ammonia is synthetically by reaction

N2 +3H2 ---> 2NH3


(a) The process is exothermic. This is because heat is released during the formation of NH3(ammonia)


(b) The moles of NH3 formed when 1 mole of N2 reacted with hydrogen is 2 moles

by use of mole ratio between N2 to NH3 wich is 1:2 the moles of NH3 is therefor = 1 x 2/1 = 2 moles


(c) The moles of NH3 produced if 18 x10^23 molecules of H2 reacted is 1.993 moles of NH3


calculation

by use of Avogadro law constant calculate the moles of H2 reacted


1 mole = 6.02 x 10^23 molecules

? = 18 x10 ^23 molecules


by cross multiplication

= 1 mole x 18 x10 ^23 / 6.02 x10^23 = 2.99moles of H2

by use of mole ratio of H2 : NH3 which is 3:2 the moles of NH3 is therefore= 2.99 x/3=1.993 moles

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lara [203]

Answer:

<u><em>This answer assumes that the strated "16.0g of iron" was meant to be 16.0 grams of iron(III) oxide.</em></u>

Explanation:

To start, the thermite equation must be balanced.

I find:

1Fe2O3 + 2Al = 1Al2O3 + 2Fe

This tells us we need 2 moles of Al for every 1 mole of Fe2O3.  

Now calculate the moles of each reactant:

Moles Fe2O3:  16.0 g/159.7 g/mole = <u>0.100 moles Fe2O3</u>

Moles Al:  8.1 /26.98 g/mole = <u>0.300 moles Al</u>

The balanced equation says that in order to react all of the Fe2O3 we'd need twice that amount (in moles) of the Al.  (0.100 moles Fe2O3)*(2) = 0.200 moles Al.

<u>Which of the two reactants is the limiting reagent?</u>

We have more than enough moles of Al to react with 0.10 moles of Fe2O3.  (We have 0.300 moles Al and all we need is 0.200 moles to react with the 0.10 moles of Fe2O3.  <em>Fe2O3 is the limiting reagent.</em>

<u><em>Calculate the maximum mass of iron of iron that could be formed using these quantities of reactants.</em></u>

The balanced equation tells us that we will obtain 2 moles of Fe for every 1 mole of Fe2O3 consumed.  Since Fe2O3 is the limiting reagent, we will assume that it completely reacts.  That means 0.1 moles of Fe2O3 is reacted.  Since we expect twice that many moles of Fe, we should obtain 0.200 moles of Fe.  At 55.85 g/mole, we should obtain:

(0.200 moles Fe)*(55.85 g Fe/mole Fe) = 11.2 grams Fe

<em></em>

<em></em>

5 0
1 year ago
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romanna [79]

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We can use the<em> Ideal Gas Law</em> to solve this problem.

pV = nRT

But n = \frac{m}{M}, so

pV = \frac{m}{M}RT and

m = \frac{pVM}{RT}\\

STP is 0 °C and 1 bar, so

m = \frac{\text{1 bar} \times \text{24 L} \times 32.00 \text{ g}\cdot\text{mol}^{-1}}{\text{0.083 14 } \text{bar}\cdot\text{L}\cdot\text{K}^{-1}\text{mol}^{-1}\times\text{273.15 K} } = \textbf{34 g}\\

7 0
3 years ago
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Answer:

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Convert given data to moles, solve in terms of moles by reaction ratios in balanced equation. After obtaining answer in moles, convert to needed dimension. In this case, no conversions are needed.

       4Fe              + 3O₂       =>          2Fe₂O₃

105g/56g·mol⁻¹

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8 0
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Answer:

See below.

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CH3CH2CH2COOH.

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H  -  C  -  C  -  C   -  C  -  OH

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