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slamgirl [31]
4 years ago
8

What is the solution to the system of equations?

Mathematics
2 answers:
sineoko [7]4 years ago
3 0

Answer:

A solution to a system of equations is a set of values for the variable that satisfy all the equations simultaneously. In order to solve a system of equations, one must find all the sets of values of the variables that constitutes solutions of the system.

Step-by-step explanation:

madam [21]4 years ago
3 0

Answer:

(2,7)

Step-by-step explanation:

n=2p+3

n=5+p

We can combine the equation to a simpler equation

5+p=2p+3 to get p=2p+-2

-p=-2 or p=2

We can plug this in to get n=5+2 to get n=7

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Suppose a circle with center (14, 9) passes through point (16, 12). Which equation represents the circle?
kumpel [21]

Answer:

The equation that represents the circle is (x-14)^{2} + (y-9)^{2} = 13

Step-by-step explanation:

Given the center of circle (14,9) passes through point (16,12)

We know that the equation of circle is

(x-h)^{2} + (y-k)^{2} = r^{2}

where (x,y) is any point on the circle, (h,k) is center of the circle and r is radius of circle.

From given data (x,y) is (16,12) and (h,k) is (14,9). Substituting these values in equation of circle, we get

(16-14)^{2} + (12-9)^{2} = r^{2}

r^{2} = 2^{2} + 3^{2}

r^{2} = 13

Substituting the values of (h,K) and  r^{2} as (14,9) and 13 respectively in equation of circle, we get

(x-14)^{2} + (y-9)^{2} = 13

Hence the equation that represents the circle is (x-14)^{2} + (y-9)^{2} = 13

7 0
3 years ago
given: sin theta= 2/3 and theta is in the second quadrant; evaluate the following expression. sin2theta
andre [41]

The value of \sin(2\theta) is -\frac {-4\sqrt 3 }9

<h3>Sine ratio </h3>

The sine ratio is given as:

\sin(\theta) = \frac23

<h3>Trigonometry</h3>

In trigonometry, we have the following ratio

\sin^2(\theta) + \cos^2(\theta) = 1

Substitute \sin(\theta) = \frac23 in the above equation

\frac 23 + \cos^2(\theta) = 1

Collect like terms

\cos^2(\theta) = 1 -\frac 23

Evaluate

\cos^2(\theta) =\frac 13

Take square roots

\cos(\theta) =\pm\frac 1{\sqrt 3 }

Rationalize

\cos(\theta) =\pm\frac {\sqrt 3 }3

From the question, \theta is in the second quadrant, and cosine is negative.

So, we have:

\cos(\theta) =-\frac {\sqrt 3 }3

In trigonometry, we have:

\sin(2\theta) = 2\sin(\theta)\cos(\theta)

So, we have:

\sin(2\theta) = 2\times \frac 23 \times -\frac {\sqrt 3 }3

\sin(2\theta) =  -\frac {-4\sqrt 3 }9

Hence, the value of \sin(2\theta) is -\frac {-4\sqrt 3 }9

Read more about trigonometry ratios at:

brainly.com/question/10417664

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