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IgorLugansk [536]
3 years ago
6

What is the solution to j + (-3) = 9?

Mathematics
1 answer:
Stels [109]3 years ago
8 0

Answer:

j = 12

Step-by-step explanation:

j + (-3) = 9

j = 12

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Show that if u+v and u-v are orthognal, then the vectors u and v must have the same length.
pashok25 [27]

Answer with Step-by-step explanation:

We are given that

u+ v and u-v are orthogonal

We have to prove that u and v must have the same length.

When two vector a and b are orthogonal then

a\cdot b=0

By using the property

(u+v)\cdot (u-v)=0

We know that

(a+b)\cdot (a-b)=\mid a\mid^2-\mid b\mid^2

\mid u\mid ^2-\mid v\mid^2=0

\mid u\mid^2=\mid v\mid^2

Magnitude is always positive

When power of base on both sides are equal then base will be equal

Therefore,

\mid u\mid=\mid v\mid

Hence, the length of vectors u and v must have the same length.

5 0
3 years ago
Plz help me it's very important I pass
Elis [28]
The answer is 30%) because all the angles of a triangle needs to add up to 180 so 180-75-75= 30
6 0
3 years ago
If you pick a card at random from a well shuffled deck, what is the probability that you get a face card or a spade?
tankabanditka [31]
P(Face card) =16/52 = 4/13
P(Spade) = 13/52 =1/4
P(Face ∪ Spade) = 4/13 + 1/4 = 29/52 = 0.557

7 0
3 years ago
Myles said that 5 x 0.13 is 6.5. Do you agree? Explain.<br><br> Brainliest if correct!
77julia77 [94]
No he is not, 10*0.13=1.3, so 5*0.13=0.65
6 0
3 years ago
Read 2 more answers
2. For a particular model of a car, a dealer offers 3 sizes of engines, 2 types of stereos, 18 body
Gnesinka [82]

The given details follow the product rule. The different model of the car available are 756.

Given that:

Engines = 3

Stereos = 2

Body=18

Color = 7

The different possibility is calculated using the following product rule:

Total =Engines \times Stereos \times Body \times Color

So, we have:

Total = 3\times 2\times 18 \times 7

Total = 756

Hence, there are 756 different models available.

Read more about product rules at:

brainly.com/question/3944602

3 0
2 years ago
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