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11111nata11111 [884]
3 years ago
12

What is 2(x+10)=2(3x-8)

Mathematics
2 answers:
Julli [10]3 years ago
7 0

Answer:

x = 9

Step-by-step explanation:

2(x+10)+2(3x)-8    Distribute

2x+20=6x-16      Subtract like terms

20=4x-16     Add 16 on both sides since it negative

36=4x        Divide 4 on both sides

x=9

Mrac [35]3 years ago
3 0

Answer:

x=9

Step-by-step explanation:

we can start by using the distributive property

so then

2x+20=6x-16

we now need to move the variables to one side and the numbers to the other

-4x=-36

x=9

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What is 2/25 of 150????
forsale [732]
12, because 150/25=6x2 is 12
7 0
4 years ago
Using the graphing function on your calculator, what is the solution to the system of equations shown below?
SpyIntel [72]
Answer:
B, x=3 y=5

Step-by-step explanation:
x=-7+2y
3y+2x=21
Substitute the x into the other equation
3y+2(-7+2y)=21
y=5
Now put the value into a desired equation
x=-7+2(5)
x=3.
The answer is x=3 and y=5

I hope this helped!
5 0
4 years ago
A CAT scan produces equally spaced cross-sectional views of a human organ that provide information about the organ otherwise obt
True [87]

Answer:

1,107 cc

Step-by-step explanation:

The 10 intervals of the scanning are

[0,1.5), [1.5,3), [3,4.5), [4.5,6), [6,7.5), [7.5,9), [9,10.5), [10.5,12), [12,13.5), [13.5,15)

The ideal thing would be to estimate the volume with the Midpoint Rule should be take n=10.

As we must use n=5, we divide the interval [0,15] in five intervals of length 15/5 = 3

[0,3], [3,6], [6,9], [9,12], [12,15] and take their midpoints

1.5, 4.5, 7.5, 10.5, and 13.5.

Now we estimate the volume V of 5 cylinders of height h=3 and area of the base A equals to the area given for the scanning where that midpoints fall

Cylinder 1

Midpoint=1.5, interval of scanning 2nd

A = 18, V= height*area of the base = 18*3 =54  cc

Cylinder 2

Midpoint=4.5, interval of scanning 4th

A = 78, V= height*area of the base = 78*3 =234  cc

Cylinder 3

Midpoint=7.5, interval of scanning 6th

A = 106, V= height*area of the base = 106*3 =318  cc

Cylinder 4

Midpoint=10.5, interval of scanning 8th

A = 129, V= height*area of the base = 129*3 =387  cc

Cylinder 5

Midpoint=13.5, interval of scanning 10th

A = 38, V= height*area of the base = 38*3 =114  cc

And the <em>estimate volume </em>is

54+234+318+387+114=1,107 cm^3

6 0
3 years ago
A box of oat cereal costs $3.90 for 15 ounces. A box of rice of cereal costs $3.30 for 11 ounces. Which box of cereal costs less
Firlakuza [10]

Answer:

The cost of per ounce of oat cereal is $0.04 less than per ounce cost of rice.

Step-by-step explanation:

Given:

Cost of 15 ounces of oat cereal box = $3.90

Cost of 11 ounces of rice box = $3.30

To compare the unit prices of the the boxes.

Solution:

Using unitary method to find the unit prices:

If 15 ounce of oat box cost =$3.90

∴ 1 ounce of oat cereal would cost = \$\frac{3.90}{15}=\$0.26

∴ Per ounce cost of oat cereal = $0.26

If 11 ounce of rice box cost =$3.30

∴ 1 ounce of rice would cost = \$\frac{3.30}{11}=\$0.3

∴ Per ounce cost of rice = $0.3

Difference in unit costs of oat and rice = \$0.3-\$0.26=\$0.04

On comparing the the unit costs of oats and rice, we find out that the cost of per ounce of oat cereal is $0.04 less than per ounce cost of rice.

3 0
4 years ago
Hint: If Angle XYZ (Exterior Angle Y) is 115, then Angle XYW (Interior Angle Y) must be 65 since they are supplementary angles.
RUDIKE [14]
Since all angles in a triangle are equal to 180 and you already have two angles you just have to subtract.
So, 180-(65 + 45)
Simplify = 180- 110
Equals = 70
4 0
3 years ago
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