C. would be my educated guess! I really hope this helps
Answer:
The farmer should expect to LOSE 10 pounds of soybeans per acre per year
Step-by-step explanation:
f(x)=-x^2 + 20x + 100
just find how many soybeans his land will yield (per acre) after 10 and 20 years:
After 10: 200 pounds of soybeans/acre
After 20: 100 pounds of soybeans/acre
Because 10 years have passed and they lost 100 pounds of soybean production per acre, the farmer should expect to lose 10 pounds of soybeans per acre per year (-10 pounds of soybeans per acre/year)
We can use this graph in the situation of an animal population of an animal species that grows exponentially until the death of Jesus, and from that point began to decrease exponentially.
It fit in the graph of the following way:
The y-axis represents the number of animals, and the x axis represents the passing of time, 0 becomes the moment in which the calendar stops being taken as before Christ and starts to be taken as after Christ.
Answer:
I would rather do the second option of which uses Compound interest that will give a profit of $47.85
Step-by-step explanation:
In this problem we will be exploring the two formulas
1. simple interest
A= P(1+r*t)
2. compound interest
A= P(1+r/n)^nt
Where A= final amount
P= initial amount
r= rate
t= time.
n= number of periods Compounded
1.given data
P= $600
r= 3%= 3/100= 0.03
t= 2 years
A= 600(1+0.03*2)
A= 600(1+0.06)
A= 600(1.06)
A= $636
Interest = 636-600= $36
2. Given data
P= $600
r= 4%= 4/100= 0.04
n= 24
t= 2
A= 600(1+0.04/24)^24*2
A=600(1+0.0016)^48
A=600(1.0016)^48
A= 600*1.07975
A= 647.85
Interest = 647.85-600= $47.85
To compare two fraction you need to rewrite the fractions so they have a common denominator.
1/2 should have been rewritten as 4/8
The answer is:
D. The fraction 1/2 should have been rewritten as 4/8.
