The area of the whole pizza must be at most 113.10 square inches in order to perfectly fit in the box. The values of r represent the half of the length of the pizza with respect to its center. In this case, the r must not exceed 6 inches (r ≤ 6 inches) in order to fit in the pizza box. On the other hand, the values of a represent the total area the pizza will occupy. In this case, the a must not exceed 113.10 square inches (a <span>≤ 113.10) </span>in order to house the pizza perfectly.
Answer:
Step-by-step explanation:
First Line:
0, 1//7, 2/7, 3/7, 4/7, 5/7, 6/7, 1, 8/7, 9/7, 10/7
Second Line:
-1/3, 0, 1/3, 1/2, 1, 4/3
Third Line:
0, 1/3, 2/3, 1, 4/3, 5/3, 2
you add the amount of people in each section that fits into the category. So, 11 people from 6-6:29 and 15 people from 6:30-6:59 and then 8 people from 7:30-7:59 so you get 34 people total
V of w sphere =
r³
Multiply by 3 on either sides to get rid of the fraction.
3V = 4
r³
Now divide either sides by 4
to isolate r³
r³
4
and 4
cancels out
= r³
Take the cube root to isolate r.
![\sqrt[3]{ \frac{3V}{4 \pi } } = \sqrt[3]{r^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3V%7D%7B4%20%5Cpi%20%7D%20%7D%20%3D%20%20%5Csqrt%5B3%5D%7Br%5E3%7D%20)
the cube root cancels the cube
![\sqrt[3]{ \frac{3V}{4 \pi } }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3V%7D%7B4%20%5Cpi%20%7D%20%7D%20)
= r
Answer:
They'll meet after 200 meters , if they simultaneously start running towards each other.
Step-by-step explanation:
Let x =distance travelled by dog and 200-x be the distance travelled by cat. Inorder to meet, the sum of their travelled distances shall be equal to 200 meters as they are far apart by 200 meters.
Dog: Distance =Speed x time: x=30t
Cat: Distance = 200-x
=24t
The sum of their distance travelled shall be 200 meters: 30t+ 24t= 200;54t=200;t=200/54=3.7secs
So they will meet after 3.7 seconds
To check:
Distance travelled by dog :x=30(3.7)
=111.11 meters
Distance travelled by cat: 24t=24(3.7)
=88.89 meters
Therefore since they are travelling towards each other and their distance apart is 200 meters, after 3.7 seconds they will meet because dog travelled 111.11 meters and cat travelled 88.89 meters and they covered already 200 meters as the sum of 111.11+ 88.89
=200 meters
