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ANTONII [103]
2 years ago
9

Which expression has a value of 8? 8x (5-4) (8 x 5) – 4 (8 x 5-4) 8 x 5 - 4

Mathematics
1 answer:
fomenos2 years ago
4 0
8x5-4 is equal to 8 if that means 8 times 5 minus 4
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It takes Dariya 35 seconds to download 5 songs from the Internet. How can the number of seconds it would take Dariya to download
netineya [11]

Answer:

49

Step-by-step explanation:

35/5=7

7x7=49 seconds

6 0
3 years ago
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Which of the following is the solution to 17 - 2x = -11?
Yuliya22 [10]

Answer:

(D)14

Step-by-step explanation:

17-2x=-11

17+11=2x

28=2x

28/2=2x/2

14=x

x=14

8 0
3 years ago
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Solve by factoring<br> : 4x2=2x+3
evablogger [386]

Answer:

1+\sqrt{13}

________

    4

Step-by-step explanation:

6 0
3 years ago
Find the obtuse angle between the following pair of straight lines.
ioda

Given:

y=-2

y=\sqrt{3}x-1

To find:

The obtuse angle between the given pair of straight lines.

Solution:

The slope intercept form of a line is

y=mx+b     ...(i)

where, m is slope and b is y-intercept.

The given equations are

y=0x-2

y=\sqrt{3}x-1

On comparing these equations with (i), we get

m_1=0

m_2=\sqrt{3}

Angle between two lines whose slopes are m_1\text{ and }m_2 is

\tan \theta=\left|\dfrac{m_2-m_1}{1+m_1m_2}\right|

Putting m_1=0 and m_2=\sqrt{3}, we get

\tan \theta=\left|\dfrac{\sqrt{3}-0}{1+(0)(\sqrt{3})}\right|

\tan \theta=\left|\dfrac{\sqrt{3}}{1+0}\right|

\tan \theta=\pm \sqrt{3}

Now,

\tan \theta= \sqrt{3} and \tan \theta=-\sqrt{3}

\tan \theta= \tan 60^\circ and \tan \theta=\tan (180^\circ-60^\circ)

\theta= 60^\circ and \theta=120^\circ

120>90, so it is an obtuse angle and 60, so it is an acute angle.

Therefore, the obtuse angle between the given pair of straight lines is 120°.

6 0
2 years ago
I need help please I don’t understand
defon

9514 1404 393

Answer:

  1. ∠EDF = 104°

  2. arc FG = 201°

  3. ∠T = 60°

Step-by-step explanation:

There are a couple of angle relationships that are applicable to these problems.

  • the angle where chords meet is half the sum of the measures of the intercepted arcs
  • the angle where secants meet is half the difference of the measures of the intercepted arcs

The first of these applies to the first two problems.

1. ∠EDF = 1/2(arc EF + arc UG)

  ∠EDF = 1/2(147° +61°) = 1/2(208°)

  ∠EDF = 104°

__

2. ∠FHG = 1/2(arc FG + arc ES)

  128° = 1/2(arc FG +55°) . . . substitute given information

  256° = arc FG +55° . . . . . . multiply by 2

  201° = arc FG . . . . . . . . . subtract 55°

__

3. For the purpose of this problem, a tangent is a special case of a secant in which both intersection points with the circle are the same point. The relation for secants still applies.

  ∠T = 1/2(arc FS -arc US)

  ∠T = 1/2(170° -50°) = 1/2(120°)

  ∠T = 60°

3 0
2 years ago
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