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3 years ago

Mendeleev used his periodic table of elements to

1 answer:

7 0

Mendeleev realized that the physical and chemical properties of elements were related to their atomic mass in a 'periodic' way, and arranged them so that groups of elements with similar properties fell into vertical columns in his table.
Mendeleev rewrote each edition of Principles of Chemistry, including all new scientific data-particularly confirmations of the periodic law-and reanalyzing difficulties that had arisen to hinder its confirmation (inert gases, radioactivity, radioactive and rare-earth elements)
he wanted to prove that he was right.

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For the following hypothetical reaction: 3A + 3B —> 2C. How many moles of B will you need to convert 4 moles of A into as man

galben [10]

Answer:

Do you still need this??

Explanation:

7 0

3 years ago

Write the reaction of reduction of iron oxide (III).

olga nikolaevna [1]

Answer: I don't know if this helps you or not, but this is from study.com:

I'm so sorry if it doesn't:

Explanation: Iron(III) oxide reacts with carbon monoxide according to the balanced equation:

Fe₂O₃ + 3CO ➡️ 2Fe + 3CO₂

A reaction mixture initially contains 23.00g Fe₂O₃ and 15.40g CO.

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3 years ago

Alguien me dice cual sería el nombre de esta formulación organica? se lo agradeceria mucho :(

amm1812

Answer:

sorry i d k for me

Explanation:

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3 years ago

What is the wavelength of spectral line resulted from the electron transition from n=3 to n=2 in a hydrogen atom.

MakcuM [25]

Answer:

$\lambda=6.56x10^{-7}m$

Explanation:

Hello there!

In this case, it possible to use the Rydberg equation in order to calculate the wavelength for this transition from n=3 to n=2 as shown below:

$\frac{1}{\lambda} =R_H(\frac{1}{n_f^2}-\frac{1}{n_i^2} )$

Thus, we plug in the corresponding energy levels and the Rydberg constant to obtain:

$\frac{1}{\lambda} =10973731.6m^{-1}(\frac{1}{2^2}-\frac{1}{3^2} )\\\\\frac{1}{\lambda} =1524129.4m^{-1}\\\\\lambda=\frac{1}{1524129.4m^{-1}} \\\\\lambda=6.56x10^{-7}m$

Best regards!

5 0

4 years ago

a weather balloon is filled with 200L of helium at 27 degree Celsius and 0.950 atm. What would be the volume of the gas at -10 d

Charra [1.4K]

Answer: The volume when the pressure and temperature has changed is 1332.53 L

Explanation:

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law. The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

We are given:

$P_1=0.950atm\\V_1=200L\\T_1=27^oC=[273+27]K=300K\\P_2=0.125atm\\V_2=?L\\T_2=-10^oC=[273-10]K=263K$

Putting values in above equation, we get:

$\frac{0.950atm\times 200L}{300K}=\frac{0.125\times V_2}{263K}\\\\V_2=1332.53L$

Hence, the volume when the pressure and temperature has changed is 1332.53 L

5 0

3 years ago