All categories

3 years ago

Does a reptile play the same role as a bird in the WNV??? PLZ HURRY PLZ

Chemistry

1 answer:

Slav-nsk [51]3 years ago

7 0

The birds could have more diseases and could pass it to other reptiles

You might be interested in

According to early chemists, which substances were classified as elements?

ladessa [460]

The best answer to your question would be B:those who could not be broken down by physical means.

6 0

3 years ago

1. What would you be wearing on the Mercury?

Vikentia [17]

Answer:

This planet rules communication, education, and commerce. Wednesdays is a day to tend the mind and care for the self. What to Wear: Mercury is represented by the color green, so wear something green on Wednesdays, be it a piece of jewelry with an emerald stone or your favorite pair of Chuck Taylors

2Metallic mercury mainly causes health effects when inhaled as a vapor where it can be absorbed through the lungs. Symptoms of prolonged and/or acute exposures include: Tremors; Emotional changes (such as mood swings, irritability, nervousness, excessive shyness)

3The four basic needs of nearly all survival situations are shelter, water, fire, and food

7 0

1 year ago

A sulfur containing amino acid is

SVETLANKA909090 [29]

Cysteine and methionine contain sulfur.

6 0

2 years ago

A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of

Stella [2.4K]

Answer:

See explanation.

Explanation:

Hello,

In this case, we can show how the empirical formula is found by following the shown below procedure:

1. Compute the moles of carbon in carbon dioxide as the only source of carbon at the products:

$n_C=0.01962molCO_2*\frac{1molC}{1molCO_2} =0.01962molC$

2. Compute the moles of hydrogen in water as the only source of hydrogen at the products:

$n_H=0.01961molH_2O*\frac{2molH}{1molH_2O}=0.03922molH$

3. Compute the mass of oxygen by subtracting the mass of both carbon and hydrogen from the 0.4647-g sample:

$m_O=0.4647g-0.01962molC*\frac{12gC}{1molC}-0.03922molH*\frac{1gH}{1molH} =0.1900gO$

4. Compute the moles of oxygen by using its molar mass:

$n_O=0.1900gO*\frac{1molO}{16gO}=0.01188molO$

5. Divide the moles of carbon, hydrogen and oxygen by the moles of oxygen (smallest one) to find the subscripts in the empirical formula:

$C=\frac{0.01962}{0.01188}=1.65\\ \\H=\frac{0.03922}{0.01188} =3.3\\\\O=\frac{0.01188}{0.01188} =1$

6. Search for the closest whole number (in this case multiply by 2):

$C_3H_6O_2$

Moreover, the empirical formula suggests this compound could be carboxylic acid since it has two oxygen atoms, nevertheless, this is not true since the molar mass is 222.27 g/mol, therefore, we should compute the molar mass of the empirical formula, that is:

$M=12*3+1*6+16*2=74g/mol$

Which is about three times in the molecular formula, for that reason, the actual formula is:

$C_9H_{18}O_6$

It suggest that the compound has a highly oxidizing character due to the presence of oxygen, therefore, we cannot predict the distribution of the functional groups as it could contain, carboxyl, carbonyl, hydroxyl or even peroxi.

Best regards.

6 0

2 years ago

239 Pu 4 He 94 2 Fill in the missing particle

lubasha [3.4K]

Answer:

la particula que queda es h2o

Explanation:

7 0

3 years ago