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marissa [1.9K]
3 years ago
15

The reaction for producing glucose in plants, called photosynthesis, is:

Chemistry
1 answer:
Firlakuza [10]3 years ago
8 0

Answer:

41.16 moles of H2O

Explanation:

Ratio for the products-reactants is 1:6, so 1 mol of glucose is produced when plants use 6 moles of water.

Then, let's make a rule of three:

1 mol of glucose is produce by using 6 moles of water

6.86 moles of glucose are produced by the use of (6 . 6.86)/1 = 41.16 moles of H2O

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Although chemical digestion occurs throughout the digestive system, it mostly occurs in the: Aesophagus and stomach B) liver and
frez [133]

Answer:

The digestive role of the liver is to produce bile and export it to the duodenum. The gallbladder primarily stores, concentrates, and releases bile. The pancreas produces pancreatic juice, which contains digestive enzymes and bicarbonate ions, and delivers it to the duodenum.

Explanation:

The chemical process of digestion begins during chewing as food mixes with ... The esophagus is a tubular organ that connects the mouth to the stomach. ... Acid reflux or “heartburn” occurs when the acidic digestive juices escape into the esophagus. ... The secretions of the liver, pancreas, and gallbladder are regulated by ...

-Both our right just choose one,

6 0
3 years ago
Pretend that you are the size of an atom, observing a reaction between a potassium atom and a fluorine atom. Write an account of
Crazy boy [7]
 <span>Each atom in an ionic compound tends either to empty or complete the shell to 8 electrons. So when the number of electrons on the external shell is near 8 , the atom tends to attract electrons to complete the shell giving a positive ion called anion 
Conversely when the number of electrons is small the atom gives these electrons to form a positive ion called a cation</span>
7 0
3 years ago
The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentrati
a_sh-v [17]

Answer : The concentration of NOBr after 95 s is, 0.013 M

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.80M^{-1}s^{-1}

t = time taken  = 95 s

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 0.86 M

Now put all the given values in above equation, we get:

0.80=\frac{1}{95}\left (\frac{1}{[A]}-\frac{1}{(0.86)}\right)

[A] = 0.013 M

Hence, the concentration of NOBr after 95 s is, 0.013 M

4 0
3 years ago
Where does the equilibrium point occur in a reaction system?
Ymorist [56]
Equilibrium occurs when the rate of the forward reaction is the same as the rate of the reverse reaction. This doesn't necessarily mean the concentrations or pressure are the same on both sides of the equation, only the rates are the same
8 0
3 years ago
How much heat is required to raise the temperature of 225 grams of ice from -26.8 °C to steam at 133 °C ?
lara [203]
<h3>Answer:</h3>

150000 J

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Thermodynamics</u>

Specific Heat Formula: q = mcΔT

  • <em>q</em> is heat (in J)
  • <em>m</em> is mass (in g)
  • <em>c</em> is specific heat (in J/g °C)
  • ΔT is change in temperature (in °C or K)

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h3>Explanation:</h3>

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] <em>m</em> = 225 g

[Given] <em>c</em> = 4.184 J/g °C

[Given] ΔT = 133 °C - -26.8 °C = 159.8 °C

[Solve] <em>q</em>

<u>Step 2: Solve for </u><em><u>q</u></em>

  1. Substitute in variables [Specific Heat Formula]:                                          q = (225 g)(4.184 J/g °C)(159.8 °C)
  2. Multiply:                                                                                                           q = (941.4 J/°C)(159.8 °C)
  3. Multiply:                                                                                                           q = 150436 J

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

150436 J ≈ 150000 J

Topic: AP Chemistry

Unit: Thermodynamics

Book: Pearson AP Chemistry

5 0
3 years ago
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