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marissa [1.9K]
3 years ago
15

The reaction for producing glucose in plants, called photosynthesis, is:

Chemistry
1 answer:
Firlakuza [10]3 years ago
8 0

Answer:

41.16 moles of H2O

Explanation:

Ratio for the products-reactants is 1:6, so 1 mol of glucose is produced when plants use 6 moles of water.

Then, let's make a rule of three:

1 mol of glucose is produce by using 6 moles of water

6.86 moles of glucose are produced by the use of (6 . 6.86)/1 = 41.16 moles of H2O

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Look at this compound, why does magnesium has dative and covalent bonds with nitrogen? ...?
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<span>The solid lines between N and Mg are actually ionic bonds. N has 5 valence electrons (2 of which are paired). Of the 3 that are unpaired, 2 are part of covalent bonds with adjacent carbon atoms. N accepts an extra electron to complete its octet, but gets a formal charge of -1. This allows for formation of an ionic bond with Mg, which is +2. Two of these charged N atoms therefore neutralize the charge of the central Mg. As for the coordinate (dative) covalent bonds, Mg has empty orbitals - the ionic bonds with the charged N atoms give it only 4/8 possible valence electrons.


The other two N atoms (dotted lines) have a formal charge of 0 since they form three covalent bonds with adjacent carbon atoms, but they still have a lone pair. Therefore, just to improve stability, each of these N atoms can "donate" its lone pair to Mg in order to complete its octet.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!



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4 0
4 years ago
Of the following elements, which one would have the smallest ionization energy ?
s2008m [1.1K]

D. Lithium or Li has the smallest ionization energy of those listed with an energy of 5,3917.

I hope that helps u!

7 0
3 years ago
Two substances A and B, initially at different temperatures, are thermally isolated from their surroundings and allowed to come
Elden [556K]

Answer:

B

Explanation:

For solving this we need a heat balance

Q_{a} = Q_{b}\\m_{a}*C_{a}*\Delta T_{a} = m_{b}*C_{b}*\Delta T_{b}

By changing the corresponding relations, we have

m_{a}*C_{a}*\Delta T_{a} = \frac{1}{2}m_{a}*4C_{a}*\Delta T_{b} \\\\\\

By cancelling similar factor, we obtain

\Delta T_{a} = 2 \Delta T_{b}\\\frac{\Delta T_{a}}{\Delta T_{b}} = 2\\

Which means that the change of temperature in A is twice the change of B

3 0
3 years ago
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