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3 years ago

The reaction for producing glucose in plants, called photosynthesis, is:

Chemistry

1 answer:

Firlakuza [10]3 years ago

8 0

Answer:

41.16 moles of H2O

Explanation:

Ratio for the products-reactants is 1:6, so 1 mol of glucose is produced when plants use 6 moles of water.

Then, let's make a rule of three:

1 mol of glucose is produce by using 6 moles of water

6.86 moles of glucose are produced by the use of (6 . 6.86)/1 = 41.16 moles of H2O

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Martian periodic table

denis23 [38]

<span>Chemists considered Martian Periodic Table as one of the most useful tools they’ve used whose purpose is to arrange the Martian elements according to their properties and their atomic number. On this periodic table, it was found out that the properties seem to vary. Dmitri Mendeleev, the first to arrange the periodic table according to atomic mass in a manner that the elements with the same properties were grouped together. It was Henry Moseley who later arranged the periodic table in accord to the increasing number of atoms per element. </span>

3 0

3 years ago

Carbordum is silicon carbide SiC a very hard material used as an abrasive on sand paper and in other applications. it is prepare

AleksandrR [38]

Answer:

4.5 kilograms of silicon dioxide is required to produce 3.00 kg of SiC.

Explanation:

The balanced equation for the reaction between silicon dioxide and carbon at high temperature is given as:

$SiO_2+3C\rightarrow SiC+2CO$

1 mole silicon dioxide reacts with 3 moles of carbon to give 1 moles of silicon carbide and 2 moles of carbon monoxide.

Mass of SiC = 3.00kg = 3000.00 g

1 kg = 1000 g

Molecular mass of SiC = 40 g/mol

Moles of SiC = $\frac{3000.00 g}{40 g/mol}= 75 mol$

According to reaction, 1 mole of SiC is produced from 1 mole of silicon dioxide.

Then 75 moles of SiC will be produce from:

$\frac{1}{1}\times 75 mol=75 mol$ of silicon dioxide.

mass of 75 moles of silicon dioxde:

$75 mol\times 60 g/mol=4500 g=4.5 kg$

4.5 kilograms of silicon dioxide is required to produce 3.00 kg of SiC.

3 0

3 years ago

How many orbitals are contained in the third main energy level and in the fifth energy level

antoniya [11.8K]

There are 9 orbitals in the third energy level and 25 orbitals in the fifth energy level.

I hope this helps you.

5 0

3 years ago

7.66 Write balanced equations for the following reactions: (a) potassium oxide with water, (b) diphosphorus trioxide with water,

White raven [17]

Explanation:

(a) potassium oxide with water

$K_2O(s)+H_2O(l)\rightarrow 2KOH(aq)$

According to reaction,1 mole of potassium oxide reacts with 1 mole of water to give 1 mole of potassium hydroxide.

(b) diphosphorus trioxide with water

$P_2O_3(s)+3H_2O(l)\rightarrow 2H_3PO_3(aq)$

According to reaction,1 mole of diphosphorus trioxide reacts with 2 moles of water to give 2 moles of phosphorus acid.

(c) chromium(III) oxide with dilute hydrochloric acid,

$Cr_2O_3(s)+6HCl(aq)\rightarrow 2CrCl_3(aq)+3H_2O(l)$

According to reaction,1 mole of chromium(III) oxide reacts with 6 moles of hydrochloric acid to give 2 moles of chromium(III) chloride and 3 moles of water.

(d) selenium dioxide with aqueous potassium hydroxide

$SeO_2 (s)+2KOH (aq)\rightarrow K_2SeO_3(aq)+H_2O(l)$