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viva [34]
2 years ago
9

Is philosophy is a branch of science. Yes or No

Chemistry
2 answers:
Alla [95]2 years ago
7 0

Answer:

No.

Explanation:

philosophy is not a science. Science uses the scientific method to form hypotheses and then test them by gathering or generating empirical evidence.

lina2011 [118]2 years ago
6 0

Answer:

no it is not branch of science

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Prepare and name an alcohol by using the following reactants
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2 years ago
Determine the concentration of a solution prepared by diluting 20.0 mL of 2.00 M NaCl to 250.0 mL. Please show your work.
yawa3891 [41]

0.16 M is the concentration of a solution prepared by diluting 20.0 ml of 2.00 M NaCl to 250.0 ml.

Explanation:

Data given:

Initial volume of NaCl, V1 = 20 ml

initial molarity of the NaCl solution = 2M

Final volume of the NaCl solution = 250 ml

final molarity of the diluted solution = ?

from the information given, the formula for dilution used is:

Minitial Vinitial = Mfinal Vfinal

putting the values in the rearranged equation:

V final = \frac{Minitial Vinitial }{Vfinal}

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6 0
2 years ago
Please with this problem
olasank [31]
<h3>Answer:</h3>

            Empirical Formula  =  C₃H₈O₃

            Molecular Formula  =  C₃H₈O₃

<h3>Solution:</h3>

Data Given:

                      Mass of Sample  =  9.2 g

                      Mass of Carbon  =  3.6 g

                      Mass of Hydrogen  =  0.8 g

                      Mass of Oxygen  =  9.2 - (3.6 + 0.8) = 4.8 g

Step 1: Calculate Moles of each Element;

                      Moles of C  =  Mass of C ÷ At.Mass of C

                      Moles of C  = 3.6 ÷ 12.01

                      Moles of C  =  0.2997 mol


                      Moles of H  =  Mass of H ÷ At.Mass of H

                      Moles of H  = 0.8 ÷ 1.01

                      Moles of H  =  0.7920 mol


                      Moles of O  =  Mass of O ÷ At.Mass of O

                      Moles of O  = 4.8 ÷ 16.0

                      Moles of O  =  0.3000 mol

Step 2: Find out mole ratio and simplify it;

                C                                        H                                     O

            0.2997                              0.7920                           0.3000

    0.2997/0.2997                  0.7920/0.2997              0.3000/0.2997

               1                                      2.64                                    1.001

Multiply by 3,

               3                               7.92 ≈ 8                                    3

Hence,  Empirical Formula  =  C₃H₈O₃

Step 3: Calculating Molecular Formula:

Molecular formula is calculated by using following formula,

                    Molecular Formula  =  n × Empirical Formula  ---- (1)

Also, n is given as,

                     n  =  Molecular Weight / Empirical Formula Weight

Molecular Weight  =  92 g.mol⁻¹

Empirical Formula Weight  =  12 (C₃) + 1.01 (H₈) + 16 (O₃)  =  92.08 g.mol⁻¹

So,

                     n  =  92 g.mol⁻¹ ÷ 92 g.mol⁻¹

                     n  =  1

Putting Empirical Formula and value of "n" in equation 1,

                    Molecular Formula  = 1 × C₃H₈O₃

                    Molecular Formula  =  C₃H₈O₃

7 0
2 years ago
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