Write the following equation in slope intercept form:<br> 10x + 2y = 24

At a snack food manufacturing facility, the quality control engineer must ensure that all products feature the appropriate expir

Helga [31]

Answer:

0.1108 = 11.08% probability that there are exactly 3 faulty candy bars among the seven.

Step-by-step explanation:

The bars are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

60 total candies means that $N = 70$

12 are faulty, which means that $k = 12$

Seven are chosen, so $n = 7$

What is the probability that there are exactly 3 faulty candy bars among the seven?

This is $P(X = 3)$ . So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 3) = h(3,70,7,12) = \frac{C_{12,3}*C_{48,4}}{C_{60,7}} = 0.1108$

0.1108 = 11.08% probability that there are exactly 3 faulty candy bars among the seven.

5 0

2 years ago

Subtraction of two real numbers may be defined of what operation

Mnenie [13.5K]

This is defined as a binary operation, the elementary arithmetic operation of subtraction. Other operations involving two real numbers are addition, multiplication, and division; in contract unary operations involve only one number and come in the form of trigonometric functions and negation, for example.

3 0

3 years ago

Solve the following equation. Remember to check for extraneous solutions 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

xxMikexx [17]

Answer:

-1, 2, 6

Step-by-step explanation:

We have to solve the equation as follows: 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

Now, we have, $\frac{1}{x-6} +\frac{x}{x-2} = \frac{4}{x^{2}-8x+12 }$