What is the principal value for cos^-1(0.69)

Mathematics

1 answer:

Paladinen [302]3 years ago

5 0

Answer:

4761/10000

Step-by-step explanation:

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Quadrilateral ABCD is similar to Quadrilateral EFGH. Diagonal AC has length 7 and diagonal EG has length 13. What is the scale f

olasank [31]

Answer:

$\large \boxed{\text{A. }\dfrac{13}{7}\text{; B. }\dfrac{17}{14} \text{; C. 507 in}^{2}}$

Step-by-step explanation:

A. Scale factor

When you dilate an object by a scale factor, you multiply its line lengths by the same number.

If EF/AB = 13/7, the scale factor is 13/7.

B. Length of EF

$\begin{array}{rcl}\dfrac{EF}{AB} & = & \dfrac{13}{7}\\\\\dfrac{EF}{\frac{17}{26}} & = & \dfrac{13}{7}\\\\EF & = & \dfrac{13}{7}\times\dfrac{17}{26}\\\\ & = &\dfrac{1}{7}\times\dfrac{17}{2}\\\\ & = & \mathbf{\dfrac{17}{14}}\\\end{array}\\\text{The length of EF is $\large \boxed{\mathbf{ \dfrac{17}{14}}}$}$

C. Area of EFGH

If the lengths in a shape are all multiplied by a scale factor, then the areas will be multiplied by the scale factor squared.

ABCD is dilated by a scale factor of 13/7, so its area is dilated by a scale factor of

$\left(\dfrac{13}{7} \right)^{2} = \dfrac{169}{49}$

The area of its dilated image EFGH is

$\text{Area of EFGH} = \text{147 in}^{2} \times \dfrac{\text{169}}{\text{49}} = 3 \times 169\text{ in}^{2} = 507 \text{ in}^{2}\\\\\text{The area of EFGH is $\large \boxed{\textbf{507 in}^{\mathbf{2}}}$}$

8 0

3 years ago

Focus on number two ok

melomori [17]

Its simple, convert 1 and 2/3 into a fraction which is 5/3 and use KCF which is Keep Change and Flip,

How this works is that you keep the first fraction, then change the division sign to a multiplication sign (Change = change the sign into its oppisite) then flip the other fraction from being 5/3 into 3/5. And then you multiply top times top and bottom times bottom. After that you simplify if you can, Hope this helped!

7 0

3 years ago

Read 2 more answers

What is the simplified form of the following expression? (n5)(n2)

Hatshy [7]

In exponent multiplication, When the bases are the same you ADD the power so it is n^7

5 0

3 years ago

A=14+(n-1)(8) solve please step by step

Rashid [163]

Answer:

$a = 8n + 6$