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Sunny_sXe [5.5K]
3 years ago
15

What is the principal value for cos^-1(0.69)

Mathematics
1 answer:
Paladinen [302]3 years ago
5 0

Answer:

4761/10000

Step-by-step explanation:


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Help!!!!!!!!!!!!!!!!!
user100 [1]

Answer:

the answer is one hundred and eight 108

Step-by-step explanation:

108 bro trust me

3 0
3 years ago
Canadians who visit the United States often buy liquor and cigarettes, which are much cheaper in the United States. However, the
victus00 [196]

Answer:

Probability of bringing a bottle of liquor into the country that is, the probability of bringing 1 bottle liquor into the country = P(B) = 0.31

The probability of not bringing a bottle of liquor into the country, that is, the probability of bringing 0 bottle liquor into the country = P(B') = 0.69

Probability distribution of bottle liquor

Let X represent the random variable of the number of bottle liquor brought into the country by a person

X | P(X)

0 | 0.69

1 | 0.31

Step-by-step explanation:

The joint probability distribution for the number of bottles of liquor and the number of cartons of cigarettes imported by Canadians who have visited the United States for 2 or more days is given in the question as

V | B

C | 0 | 1

0 | 0.62 | 0.16

1 | 0.07 | 0.15

Note that B = bottle liquor

C = Carton cigarettes

V is each variable

Let the probability of bringing a bottle of liquor into the country be P(B), that is, the probability of bringing 1 bottle liquor into the country.

The probability of not bringing a bottle of liquor into the country is P(B'), that is, the probability of bringing 0 bottle liquor into the country.

Let the probability of bringing a carton of cigarettes into the country be P(C), that is, the probability of bringing 1 carton cigarettes into the country.

The probability of not bringing a carton of cigarettes into the country is P(C'), that is, the probability of bringing 0 carton cigarettes into the country.

From the joint probability table, we can tell that

P(B n C) = 0.15

P(B n C') = 0.16

P(B' n C) = 0.07

P(B' n C') = 0.62

Find the marginal probability distribution of the number of bottles imported.

Probability of bringing a bottle of liquor into the country that is, the probability of bringing 1 bottle liquor into the country = P(B)

P(B) = P(B n C) + P(B n C') = 0.15 + 0.16 = 0.31

The probability of not bringing a bottle of liquor into the country, that is, the probability of bringing 0 bottle liquor into the country = P(B')

P(B') = P(B' n C) + P(B' n C') = 0.07 + 0.62 = 0.69

Probability distribution of bottle liquor

Let X represent the random variable of the number of bottle liquor brought into the country by a person

X | P(X)

0 | 0.69

1 | 0.31

Hope this Helps!!!

8 0
3 years ago
8142 divided by 22 plz help cause idk this and it's in my homework and I keep getting it wrong
jek_recluse [69]
8142/22 = 370.09 repeating
6 0
3 years ago
It is 20 minutes before 8:00 in the morning. What time is this?
saveliy_v [14]
7:40 am because you subtract 8:00 by :20 

7 0
3 years ago
Read 2 more answers
Find the value of x<br><br> If 100x =265.0
kakasveta [241]
To solve:

1) Divide both sides by 100

100x/100 = 265/100

x = 2.65
8 0
4 years ago
Read 2 more answers
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