3 years ago

What is the principal value for cos^-1(0.69)

Mathematics

1 answer:

Paladinen [302]3 years ago

5 0

Answer:

4761/10000

Step-by-step explanation:

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What is the volume of the cone in the picture ifS=5 and R= 3? (V=

babunello [35]

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8 0

3 years ago

A sample size of n = 64 is drawn from a population whose standard deviation is o = 5.6.

AlekseyPX

Answer:

The margin of error for a 99% confidence interval for the population mean is 1.8025.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

In this problem:

$\sigma = 5.6$

$M = 2.575*\frac{5.6}{\sqrt{64}} = 1.8025$

The margin of error for a 99% confidence interval for the population mean is 1.8025.

5 0

3 years ago

How much will $850 amount to be in three years if it is invested at 8% interest compounded quarterly for 3 years? A. $886.47 B.

Dimas [21]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{compounded amount}\\
P=\textit{original amount deposited}\to &\$850\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, so four times}
\end{array}\to &4\\

t=years\to &3
\end{cases}$