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AlekseyPX
3 years ago
9

A solution that dissloves completely is called a?

Chemistry
2 answers:
WINSTONCH [101]3 years ago
5 0
If by “dissolves completely”, you mean that the solution looks uniform, then it would be called a homogeneous solution.
snow_tiger [21]3 years ago
3 0

soluble substances dissolves in solvents

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A voltaic cell has one half-cell with a Cu bar in a 1.00 M Cu²⁺ salt, and the other half-cell with a Cd bar in the same volume o
Verizon [17]

The E^o_{cell} of the voltaic cell is 0.743 V. The ΔG°of the given cell is -143.377 kJ and K is 1.35 × 10²⁵

<h3>What is a voltaic cell?</h3>

A voltaic cell often called a galvanic cell, is an electrochemical device that produces electricity through spontaneous redox processes.

It is divided into two distinct half-cells. A half-cell is made up of an electrode (a metal strip, M) dissolved in a solution containing Mn⁺ ions. M can be any metal.

A wire from one electrode to the other connects the two half-cells. Additionally, a salt bridge links the two half-cells.

To solve the question, we need to write the equations of two half-cells

At the anode, oxidation occurs

Cd(s) \rightarrow Cd^{2+}(aq) + 2e^-

E° = -0.403 V

At the cathode, reduction occurs

Cu^{2+}(aq) + 2e^- \rightarrow Cu(s)

E° = 0.34 V

Overall reaction:

Cd(s) + Cu^{2+}(aq) \rightarrow Cd^{2+}(aq) + Cu(s)

We know

E^o_{cell} = E^o_{cathode} - E^o_{anode}

= 0.34 -(-0.403) = 0.743 V

Also,

ΔG° = -nFE^o_{cell}

Where, n = no of electrons gained or lost

F = Faraday constant

E^o_{cell} = standard potential

ΔG° = -2×96485×0.743 = -143376.71 J = -143.377 kJ

Also,

ΔG° = -RTlnK

-143.377 = -8.314 × 10-3 × 298 × lnK

lnK = 57.87

K = 1.35 × 10²⁵

Hence, The E^o_{cell} of the voltaic cell is 0.743 V. The ΔG°of the given cell is -143.377 kJ and K is 1.35 × 10²⁵

Learn more about Voltaic cell:

brainly.com/question/4430225

#SPJ4

6 0
1 year ago
For the following reaction, 27.5 grams of hydrochloric acid are allowed to react with 56.7 grams of barium hydroxide.
Nesterboy [21]

Answer:

i) 68.92 g

ii) Ba(OH)₂

iii) 3.35 g

Explanation:

This is a chemical reaction where an acid and a base are reacting. To get the mass of the product, in this case, the barium chloride, we need to write the reaction with the correct formula of the compound and then, balance, if it's neccesary.

The chemical reaction with formulas is:

HCl + Ba(OH)₂ ------> BaCl₂ + H₂O

Now, it's time to balance the equation:

2HCl + Ba(OH)₂ ------> BaCl₂ + 2H₂O

We have the balanced equation, now let's find out how much of the product will be formed. In this case, we have to use stochiometry with moles, which is the easier way to get the quantity of the products. With the balanced equation we can know which is the limiting reactant and the excess. Let's get the moles of the acid and the hydroxide.

The molecular mass of HCl and hydroxide reported is 36.45 g/mol and 171.34 g/mol so the moles are:

n HCl = 27.5/36.45 = 0.754 moles

n Ba(OH)₂ = 56.7/171.34 = 0.331 moles

Now, let's find the stochiometry to get the limiting reactant:

2 mole HCl --------> 1 mole Ba(OH)₂

0.754 moles ----------> X

X = 0.754 / 2 = 0.377 moles of Ba(OH)₂ are needed, but we only have 0.331 moles, this means that the Ba(OH)₂ is the limiting reactant while the HCl is the excess reactant.

Now that we know that the excess reagent is the HCl, let's see how much of it remains after the reaction is completed:

moles of HCl that reacted: 0.331 * 2 = 0.662 moles

remanent moles of HCl = 0.754 - (0.662) = 0.092 moles

Then the mass:

m = 0.092 * 36.45 = 3.35 g of HCl

Now, let's see how much of BaCl₂ is formed, knowing that the moles of Ba(OH)₂ are the same moles of BaCl₂:

moles Ba(OH)₂ = moles BaCl₂ = 0.331 moles

The reported molar mass of BaCl₂ is 208.23 g/mol so the mass:

m BaCl₂ = 0.331 * 208.23 = 68.92 g

4 0
3 years ago
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