The mass of nitrogen gas that participated in the chemical reaction is 1.54g
HOW TO CALCULATE MASS OF AN ELEMENT:
- Mass of a substance can be calculated by multiplying the number of moles in mol of the substance by its molecular mass in g/mol. That is;
- mass (M) = molar mass (MM) × number of moles (n)
According to this question, a chemist determines by measurements that 0.0550 moles of nitrogen gas (N2) participate in a chemical reaction.
- The molecular mass of nitrogen gas (N2) = 14.01(2)
= 28.02g/mol
Hence, the mass of the nitrogen gas that participated in the chemical reaction is calculated as follows:
- Mass (g) = 0.0550 mol × 28.02 g/mol
Therefore, the mass of nitrogen gas that participated in the chemical reaction is 1.54g
Learn more: brainly.com/question/18269198
Answer is (2) - hydrogen carbonate
<em>Explanation:</em>
NaHCO₃ is an ionic compound which is made from Na⁺ and HCO₃⁻ ions. The decomposition is
NaHCO₃ → Na⁺ + HCO₃⁻
Among the resulted ions, Na⁺ is a monatomic ion while HCO₃⁻ is a polyatomic ion.
<em>Polyatomic ions mean ions which are made of two or more different atoms.</em>
HCO₃⁻ is made from 3 atoms as H, C and O. The name of HCO₃⁻ ion is bicarbonate or hydrogen carbonate.
Answer:
At STP one mole of any gas occupies a volume of 22.4 L: this is the molar volume.
Explanation:
Many organisms need clean drinking water and we also need moisture in the air for us to stay hydrated
Moles of Na theoretically extract : 10.256
<h3>Further explanation</h3>
Given
600 g of NaCl
Required
moles of Na
Solution
Na can be electrolyzed from NaCl(molten)
Na⁺ + e⁻⇒ Na
Cl⁻⇒1/2 Cl₂ + e⁻
Overall reaction :
NaCl⇒Na + 1/2 Cl₂ x2
<em>2NaCl⇒2Na + Cl₂</em>
mol of NaCl(MW=58.5 g/mol) :
= 600 g : 58.5 g/mol
= 10.256
From the equation, mol ratio of NaCl : Na = 2 : 1, so :
mol Na = mol NaCl = 10.256
