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3 years ago

Only need help with 22

Mathematics

1 answer:

zzz [600]3 years ago

4 0

~hi

what you need to do is multiply the fraction

-s and that is what the awnser is

~bie~

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Brainliest if correct!! Does this graph show a function?

Masteriza [31]

Answer:

No, it is not a function.

Step-by-step explanation:

A function graph are graphs where the lines do not connect. Since the shape is a circle, many lines in the graph are connecting.

8 0

2 years ago

A pizza with a diameter of 8 inches costs $10 and a pizza

Rina8888 [55]

Answer:

8 inch is your best buy

Step-by-step explanation:

8inch diameter =10 dollars

5 inch radius = 12 dollars

so if we get each equal to the diameter it should be 10 inch and that would be 24 dollars vs . 8 in for 10 dollars. So best buy would be 8 inch

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2 years ago

What is 2/3+(-1/6) please I need the answer

Amiraneli [1.4K]

Answer:

it is 1/2

Step-by-step explanation:

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2 years ago

Read 2 more answers

Which equation represents the line that passes through the point (4, -5) and is perpendicular to the line x + 2y = 5?

Lerok [7]

Answer:

y = 2x - 13

Step-by-step explanation:

Equation of a line is y = mx + c, m is the gradient and c is the intercept

The line passes through points 4 and -5, x is 4 and y is -5

-5 = 4m + c

When two lines are perpendicular, the products of their gradients are equal to -1, m1 * m2 = -1

x + 2y = 5

2y = -x + 5

y = (-1/2 * x) + 5

therefore m = -1/2

m1 * m2 = -1

m * -1/2 = -1

-m = -2 , therefore m = 2

-5 = 4 * 2 + c

c = -5 - 8, which is -13

Therefore the equation for the line is

y = 2x - 13

7 0

3 years ago

A rumor spreads through a small town. Let y ( t ) be the fraction of the population that has heard the rumor at time t and assum

Ivan

Answer:

Differential equation

$\frac{dy}{dt} =ky(1-y)$

Solution

$y=\frac{1}{1+4e^{-0.327t}}$

Value of constant k=0.327 days^(-1)

The rumor reaches 80% at 8.48 days.

Step-by-step explanation:

We know

y(t): proportion of people that heard the rumor

y'(t)=ky(1-y), rate of spread of the rumor

Differential equation

$\frac{dy}{dt} =ky(1-y)$

Solving the differential equation

$\frac{dy}{y(1-y)}=k\cdot dt \\\\\int \frac{dx}{y(1-y)} =k \int dt \\\\-ln(1-\frac{1}{y} )+C_0=kt\\\\1-\frac{1}{y} =Ce^{-kt}\\\\\frac{1}{y} =1-Ce^{-kt}\\\\y=\frac{1}{1-Ce^{-kt}}$

Initial conditions:

$y(0)=0.2\\y(3)=0.4\\\\y(0)=0.2=\frac{1}{1-Ce^0}\\\\1-C=1/0.2\\\\C=1-1/0.2= -4\\\\\\y(3)=0.4=\frac{1}{1+4e^{-3k}} \\\\1+4e^{-3k}=1/0.4\\\\e^{-3k}=(2.5-1)/4=0.375\\\\k=ln(0.375)/(-3)=0.327\\\\\\y=\frac{1}{1+4e^{-0.327t}}$

Value of constant k=0.327 days^(-1)

At what time the rumor reaches 80%?

$y(t)=0.8=\frac{1}{1+4e^{-0.327t}} \\\\1+4e^{-0.327t}=1/0.8=1.25\\\\e^{-0.327t}=(1.25-1)/4=0.0625\\\\t=ln(0.0625)/(-0.327)=8.48$

The rumor reaches 80% at 8.48 days.

8 0

3 years ago