Question

On a coordinate plane, a curved line with minimum values of (negative 1.56, negative 6) and (3, 0), and a maximum value of (1.2, 2.9), crosses the x-axis at (negative 2.5, 0), (0, 0), and (3, 0), and crosses the y-axis at (0, 0). Which interval for the graphed function has a local minimum of 0? [–3, –2] [–2, 0] [1, 2] [2, 4]

Answer 1

Answer:

$[2,4]$

Step-by-step explanation:

On a coordinate plane, a curved line has minimum values of (negative 1.56, negative 6) and (3, 0). This means

1) when $x=-1.56$, the minimum value of the function is $y_{min}=-6$

2) when $x=3,$ the minimum value of the function is $y_{min}=0$

Hence, the graphed function has a local minimum of 0, when $x=3.$

Therefore, the interval which contains this value of x is $[2,4]$ because $x=3\in [2,4].$

Answer 2

Answer: [2,4]

Step-by-step explanation:

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