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3 years ago

12

How to solve for y if the equation is y=5/2x + 5 if x is zero

2 answers:

alexgriva [62]3 years ago

6 0

Q, y=5/2x+x if x is zero

An, ( y=5/2×0+5 ) as you know if i multiply number to zero you get zero so "x" change to the zero you get
( y=0+5 )= ( y=5 ) that is your answer

Karolina [17]3 years ago

5 0

$y=\dfrac{5}{2}\cdot0+5\\
y=0+5\\
y=5$

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3t + 35=6 Enter your answer in the box.

IrinaVladis [17]

3t+35−35=6−35

3t=−29

3t/3=-29/3

<u>Answer is t=-29/3</u>

Hope this helps!

8 0

3 years ago

Read 2 more answers

Find out the answers to this

meriva

Answer:

$\tan \theta = - \frac{1}{5} = - 0.2$

$\cos \theta = 0.98$

$\sin \theta = - 0.196$

Step-by-step explanation:

It is given that $\cot \theta = - 5$ and $\theta$ is in the fourth quadrant.

So, only $\cos \theta$ will have positive value and $\sin \theta$ , $\tan \theta$ will have negative value.

Now, $\cot \theta = - 5$

⇒ $\tan \theta = \frac{1}{\cot \theta} = -\frac{1}{5}$ (Answer)

We know, that $\sec^{2} \theta - \tan^{2} \theta = 1$

⇒ $\sec \theta = \sqrt{1 + \tan^{2} \theta } = \sqrt{1 + (- \frac{1}{5} )^{2} } = 1.019$

{Since, $\cos \theta$ is positive then $\sec \theta$ will also be positive}

⇒ $\cos \theta = \frac{1}{\sec \theta} = \frac{1}{1.0198} = 0.98$ (Answer)

We know, that $\csc^{2} \theta - \cot^{2} \theta = 1$

⇒ $\csc \theta = - \sqrt{1 + \cot^{2} \theta } = - \sqrt{1 + (- 5 )^{2} } = - 5.099$

{Since, $\sin \theta$ is negative then $\csc \theta$ will also be negative}

⇒ $\sin \theta = \frac{1}{\csc \theta} = \frac{1}{- 5.099} = - 0.196$ (Answer)

4 0

3 years ago

Simplify square root

NemiM [27]

Answer:

C

Step-by-step explanation:

look up rules of multiplying radicals.

You can multiply the radicands (the number inside the square root) then take the square root of the new number.

3*21 = 63

Factor 63 into 3*3*7

Pull out 3^2 from inside the square root

leaves you with 3sqrt7 or answer C

7 0

3 years ago

What is the solution to 5x < 30

max2010maxim [7]

Let's solve your inequality step-by-step.

5x<30

Step 1: Divide both sides by 5.

5x

5

<

30

5

x<6

7 0

3 years ago

Aya = a1 + (n - 1)d

Alenkasestr [34]

Answer:

The 26th term of an arithmetic sequence is:

$a_{26}=67$

Hence, option A is true.

Step-by-step explanation:

Given

a₁ = -33

d = 4

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

substituting a₁ = -33 and d = 4 in the nth term of the sequence

$a_n=-33+\left(n-1\right)4$

$\:a_n=-33+4n-4$

$a_n=4n-37$

Thus, the nth term of the sequence is:

$a_n=4n-37$

now substituting n = 26 in the nth term to determine the 26th term of the sequence

$a_n=4n-37$

$a_{26}=4\left(26\right)-37$

$a_{26}=104-37$

$a_{26}=67$

Therefore, the 26th term of an arithmetic sequence is:

$a_{26}=67$

Hence, option A is true.

7 0

2 years ago