Step-by-step explanation:
We khow the sum and the product of the zeroes of this quadratic polynomial
Here is a trick :
when we khow the sum S and the product P ofvtwo numbers we can find them by solving :
x²-Sx+p=0
here S= -8 and P=12
so:
x²+8x+12=0
Let Δ be the discrminant of this equation: a= 1 , b= 8 and c=12
Δ= 8²-4*12 =16
the zeros are:
(-8-4)/2= -6
(-8+4)/2 = -2
verify:
-6+(-2)= -8
-2*(-6)= 12
now the polynomial quadratic is:
(x+6)(x+2)
Answer:
n² - 6n - 16
Step-by-step explanation:
As per the question,
We have been provided the equation
(n-8)(n+2)
To find the product, we have to multiply the both term,
(n - 8) (n + 2)
= n (n + 2) - 8 (n + 2)
= (n² + 2n) - (8n + 16)
= n² + 2n - 8n - 16n
= n² - 6n - 16
Hence, the required answer of the product of (n-8)(n+2) = n² - 6n - 16.
9514 1404 393
Answer:
x = 0
Step-by-step explanation:
You can eliminate parentheses and subtract 50.
5(2x +10) = 50
10x +50 = 50 . . . . use the distributive property
10x = 0 . . . . . . . . . subtract 50 from both sides
x = 0 . . . . . . . . . . . divide by 10
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<em>Check</em>
5(2·0 +10) = 50
5(10) = 50 . . . . true
<span>If you're trying to solve for x, then there is no solution. Since the left side is positive, the inequality has no solution over the domain.</span>
Answer:
idk help
Step-by-step explanation:
