Here's link to the answer:
tinyurl.com/wpazsebu
Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
10
Step-by-step explanation:
Answer:
-x with an exponent of 2 + y with an exponent of 2
Step-by-step explanation:
good luck
