Question

If p is inversely proportional to the square of q, and p is 16 when q is 11, determine p

Answer 1

Answer:

p= 121

Step-by-step explanation:

p$\alpha$ $\frac{1}{q^{2} }$

p=k/$q^{2}$

k=p$q^{2}$

Get the value of your constant k

k=(16)($11^{2}$)

k= 1936

p= $\frac{1936}{q^{2} }$

When q=4

p=  $\frac{1936}{4^{2} }$

p= 121

Answer 2

Answer:

p = 121

Step-by-step explanation:

inveresly proportional

pq² = k

find k the constant of proportionality

p is 16 when q is 11,

16 * 11² = k

k = 1,936

----------------------------

pq² = 1,936

determine p when q is equal to 4.

p * 4² = 1,936

16p = 1,936

p = 1,936/16

p = 121