How many times does 16 go into 36?

Mathematics

1 answer:

Nady [450]3 years ago

4 0

2.25 times............................................

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Help me solve this by multiplication or linar combination please

patriot [66]

X would be equal to 0 while y would be equal to -1
-20(0)+6(-1)=-6
-10(0)-4(-1)=4

4 0

4 years ago

Which shows 2-6 ///////////////////////////////////////////////////////

Leokris [45]

Answer:

Step-by-step explanation:

(1/2⁶)

7 0

3 years ago

Read 2 more answers

3(x-2)+2(x+1)=-14<br> plz show work

Rom4ik [11]

Hello!

First, let's write the problem.
$3\left(x-2\right)+2\left(x+1\right)=-14$
Apply the distributive property on the left side of the equation.
$=3x-6+2x+2$
Add like terms.
$=5x-4$
Let's plug that in into the original equation.
$5x-4=-14$
Add 4 to both sides.
$5x-4+4=-14+4$
$5x=-10$
Divide both sides by 5.
$\frac{5x}{5}=\frac{-10}{5}$

Our final answer would be,
$x=-2$

You can feel free to let me know if you have any questions regarding this!
Thanks!

- TetraFish

5 0

3 years ago

Read 2 more answers

Please help radical expression dividing

77julia77 [94]

$\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad 
\begin{cases}
63=3\cdot 3\cdot 7\\
6=2\cdot 3
\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}
\\\\\\
\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}$

$\bf \textit{now, rationalizing the denominator}\\\\
\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}
\\\\\\
\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}$

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.

6 0

3 years ago

May I get help on these questions, please?

Virty [35]

Hello! here are the basic rules that you need to know to solve these problems:

a diameter is 2 × the radius
the circumference rule is 2×π×radius

I will solve the first question to show how to format.

1: 5/2=2.5
2×2.5×π=5×π=15.7

5 0

2 years ago