Answer:
The chance that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses is P=0.0488.
Step-by-step explanation:
To solve this problem we divide the tossing in two: the first 5 tosses and the last 5 tosses.
Both heads and tails have an individual probability p=0.5.
Then, both group of five tosses have the same binomial distribution: n=5, p=0.5.
The probability that k heads are in the sample is:
Then, the probability that exactly 2 heads are among the first five tosses can be calculated as:
For the last five tosses, the probability that are exactly 4 heads is:
Then, the probability that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses can be calculated multypling the probabilities of these two independent events:
Answer:
The bullet point between the numbers means times in this case, in some other cases it would mean "and" also known as plus. Therefore, the correct answer is the second one.
Step-by-step explanation:
In each half unit cube there is 6 cubes. ⇒
6 + 6 + 6 = 18 ⇒
But, this is not one of the options.⇒
So, we have to make the equation a bit different to solve it. ⇒
2 x 3 x 2, is the first option. ⇒
This is incorrect, as it equals 12. ⇒
The sum we are looking for is 18. ⇒
The second answer is 2 x 3 x 3. ⇒
This equals 18, we have found the correct answer. ⇒
So, there are a total of 3 half-unit cubes. ⇒
There are a total of 18 cubes. ⇒
I hope this helps!
Answer: 38
Step-by-step explanation: to evaluate an expression for these variables, plug in those numbers for the variables.
Plugging in -1 for y and -19 for z gets you this:
-2(-1)^2(-19)
Now simplify according to order of operations (PEMDAS - parenthesis exponents multiplication/division addition/subtraction)
-1^2 = 1
-2(1) = -2
-2(-19) = 38
Your answer is 38
1 1/16 is it's simplest form.
