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qwelly [4]
3 years ago
6

What is 95% as a fraction in simplest form

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
6 0
The answer is 19 over 20
MaRussiya [10]3 years ago
5 0
95% as a fraction in simplest form is 19/20. 95/100=95%. 95/100 divided by 5/5 is 19/20 and that is the simplest form.
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If y(x) = 4x, what is x when y(x) = 4<br><br> A. 1<br><br> B. 4<br><br> C. 2<br><br> D. 0
Eva8 [605]

Answer:

1

Step-by-step explanation:

cause if :

y=4

4(x)=4

4(1)=4

4=4

hope this helps

4 0
3 years ago
Find the equation of the plane through the point p=(5,5,4)p=(5,5,4) and parallel to the plane 5x+2y−z=−6.
Anna35 [415]
The unit normal for the given plane is <5,2,-1>.
The equation of the plane parallel to the given plane passing through (5,5,4) is therefore
5(x-5)+2(y-5)-1(z-4)=0
simplify =>
5x+2y-z=25+10-4=31

Answer: the plane through (5,5,4) parallel to 5x+2y-z=-6 is 5x+2y-z=31
7 0
3 years ago
Yes help pls giving brainlest
lesya [120]

Answer:

1 and 7/12 hours

Step-by-step explanation:

2 and 1/3 is the whole. You need to subtract 3/4. To bring both of these to the same denominator, multiply each fraction by the others denominator. That means 1/3 is now 4/12 and 3/4 is now 9/12. They can now be subtracted. 2 and 4/12 - 9/12 = 1 and 7/12.

5 0
3 years ago
Read 2 more answers
Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re
fiasKO [112]

Answer: R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts 38^{\circ} angle to each other

The resultant of the two forces is given by

\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}

Insert the values

\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb

Resultant makes an angle of

\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}

So, the resultant makes an angle of 22.57^{\circ} with 9 lb force

Angle made with 13 lb force is 38^{\circ}-22.57^{\circ}=15.43^{\circ}

7 0
3 years ago
Read 2 more answers
Answer quick please
Goryan [66]
The answer is B you jump -5
3 0
3 years ago
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