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3 years ago

Can't figure this out

Mathematics

1 answer:

8090 [49]3 years ago

7 0

Divide each number by 3 Then subtract the numbers you got from the answers that you divided

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I need this by tomorrow can someone help me, please

steposvetlana [31]

Answer:

no seeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeereeeeeeee

4 0

3 years ago

Read 2 more answers

Work out, giving your answer as a mixed number:<br> 4 2/3 + 1 3/4 =

hammer [34]

4x3+2 = 14/3 —> 56/12
1x4+3 = 7/4 —> 21/12
56-21 is equal to 35/12
Which is 2 and 11/12

4 0

3 years ago

Read 2 more answers

A stone is an Old English unit of weight and equal to 14 slug. How many kilograms are there in 6 stones? (1 slug = 14.59 kg) Ans

Ber [7]

Answer:

1225.56 kg

Step-by-step explanation:

1 stone = 14 slugs

1 slug = 14.59 kg

$\text{6 stones} ( \dfrac{14 slug}{1 stone})(\dfrac{14.59 kg}{1 slug})$

numerator 6 * 14 * 14.59 = 1225.56 kg

denominator = 1

Answer 1225.56 kg in 6 stones

8 0

3 years ago

Start at 125 create a pattern that subtracts 6 from each number

igor_vitrenko [27]

In this question, you are asked to make a pattern start with 125 with 6 less number each pattern. Then the pattern equation would be: 125-6x where x is determined by the position of the number.

The question doesn't specify how many numbers in the pattern that needs to be written but the pattern should be like this: 125, 119, 113, 107, 101, 95, 89, 83, 77

8 0

3 years ago

With Obesity on the rise, a Doctor wants to see if there is a linear relationship between the Age and Weight and estimating a pe

Romashka [77]

Answer:

112.569 ( D )

Step-by-step explanation:

Applying the estimated Regression Equation

y = b1X1 + b2X2 + a

b1 = ((SPX1Y)*(SSX2)-(SPX1X2)*(SPX2Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 596494.5/635355.88 = 0.93884

b2 = ((SPX2Y)*(SSX1)-(SPX1X2)*(SPX1Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 196481.5/635355.88 = 0.30925

a = MY - b1MX1 - b2MX2 = 149.25 - (0.94*61.31) - (0.31*193.88) = 31.73252

y = 0.939X1 + 0.309X2 + 31.733

For x1 ( age ) =39, and x2(weight) =143

y = (0.93884*39) + (0.30925*143) + 31.73252= 112.569

where

Sum of X1 = 981

Sum of X2 = 3102

Sum of Y = 2388

Mean X1 = 61.3125

Mean X2 = 193.875

Mean Y = 149.25

attached is the Tabular calculation of the required values needed for estimated regression equation

8 0

3 years ago