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valkas [14]
3 years ago
12

Can't figure this out

Mathematics
1 answer:
8090 [49]3 years ago
7 0
Divide each number by 3 Then subtract the numbers you got from the answers that you divided
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To eliminate the x terms and solve for y in the fewest steps, by which constants should the equations be multiplied by before ad
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Kona wants to bake 30 loaves of bananas bread and nut bread one is 2.50 and other is 2.75 she wants to make are lasts 44$ write
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6 0
2 years ago
A consumer testing service tested whether the average baking time of whole wheat bread in gas ovens was less than the average ba
vichka [17]

Answer:

Part 1) The explanatory variable is the type of oven

It is a categorical variable

Part 2) The response variable is the baking time

It is a quantitative variable

part 3) two-sample z-test for proportions should be used for the test

Step-by-step explanation:

An explanatory variable is an independent variable that is not affected by all other variables. In this experiment, the type of oven is the input variable and it  is not affected by any other variable

A categorical variable is one that has two or more categories without any intrinsic ordering of the categories. The type of oven is either gas or electric, so it is categorical.

A response variable is a dependent variable whose variation depends on other variables. The baking time in this experiment depends on the type of oven used

A quantitative variable is one that take on numerical values.

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5 0
3 years ago
In a group of 10 ​kittens, 5 are female. Two kittens are chosen at random. ​a) Create a probability model for the number of male
olya-2409 [2.1K]

Answer:

(b) Expected number of male kitten E(x) = 1

(c) Standard deviation is ±\frac{2}{3}.

Step-by-step explanation:

Given that,

Number of kittens in a group are 10. Out of these 5 are female.

To find:- (a) create a probability model of male kitten chosen.

    So,  total number of kitten = 10

           number of female kitten = 5    

then, Number of male kitten = 10-5= 5

Now total number of ways to choosing two kittens from group of 10 = ^{10} C_{2}

                                                                                                                 = \frac{10!}{2!\times8!}

                                                                                                                 = 45

for choosing (i) No male P(x=0) = P(Two female) =  \frac{^{5} C_{2}}{45}

                                                                           = \frac{2}{9}

                     (ii) 1 male P(x=1) = P(1 male and 1 female) = \frac{^{5} C_{1}\times^{5} C_{1}}{45} =  \frac{25}{45} =\frac{5}{9}

                     (iii) 2 male P(x=2)= P(2 male) =\frac{^{5} C_{2}}{45} =  \frac{2}{9}

      x_{i}                             0                     1                      2

P(X=x_{i})                           \frac{2}{9}                      \frac{5}{9}                      \frac{2}{9}

(b) what is expected number of male kittens chosen ?

    Expected number of male kitten E(x) =  o\times \frac{2}{9} + 1\times \frac{5}{9} + 2\times\frac{2}{9}

                                                                  = 1

(c) what is standard deviation ?

                              \sigma(x) = \sqrt{ (E(x^{2} )-(Ex)^{2})

No,                          

                               Ex^{2} =o\times \frac{2}{9} + 1\times \frac{5}{9} + 4\times\frac{2}{9}

                                       = \frac{13}{9}

                               \sigma(x)=\sqrt{\frac{13}{9} - 1 }=\sqrt{\frac{4}{9} }  

                                       = ± \frac{2}{3}

                               

6 0
2 years ago
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