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3 years ago

What is 6 to the power of negative 2

Mathematics

1 answer:

Travka [436]3 years ago

8 0

Answer:

0.0277777778

Step-by-step explanation:

Instead of multiplying you divide

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2 years ago

Let sin(−θ)=−3/5 and tanθ>0. What is the value of cos(−θ)?

Jobisdone [24]

Answer:

The value of Cos (-Ф) $\dfrac{\textrm 4}{\textrm 5}$ .

Step-by-step explanation:

Given Trigonometric function as :

sin( - Ф ) = $\frac{- 3}{5}$

- sin Ф = $\frac{- 3}{5}$

So, sin Ф = $\frac{ 3}{5}$

Now, as sin Ф = $\dfrac{\textrm perpendicular}{\textrm hypotenuse}$

So , $\dfrac{\textrm perpendicular}{\textrm hypotenuse}$ = $\frac{ 3}{5}$

So, perpendicular = 3

And hypotenuse = 5

Now,<u> From Pythagoras Theorem</u>

Base ² = Hypotenuse² - Perpendicular²

Or, Base ² = 5² - 3²

Or, Base ² = 25 - 9

Or, Base ² = 16

∴ Base = $\sqrt{16}$

I.e Base = 4

Now, Cos Ф = $\dfrac{\textrm base}{\textrm hypotenuse}$

So, Cos Ф = $\dfrac{\textrm 4}{\textrm 5}$

Now , Since

Cos ( - Ф ) = Cos Ф

So, Cos ( - Ф ) = Cos Ф = $\dfrac{\textrm 4}{\textrm 5}$

Hence The value of Cos (-Ф) $\dfrac{\textrm 4}{\textrm 5}$ . Answer

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2 years ago

Find the equation of the inverse.<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%7B2%7D%5E%7Bx%20%2B%205%7D%20%20-%206" id="TexF

Contact [7]

Find the equation of the inverse.

$y = {2}^{x + 5} - 6$

we have

$y=\mleft\{2\mright\}^{\mleft\{x+5\mright\}}-6$

step 1

Exchange the variables

x for y and y for x

$x=\{2\}^{\{y+5\}}-6$

step 2

Isolate the variable y

$(x+6)=2^{(y+5)}$

apply log both sides

$\begin{gathered} \log (x+6)=(y+5)\cdot\log (2) \\ y+5=\frac{\log (x+6)}{\log (2)} \\ \\ y=\frac{\log(x+6)}{\log(2)}-5 \end{gathered}$

step 3

Let

$f^{(-1)}(x)=y$

therefore

the inverse function is

$f^{(-1)}(x)=\frac{\log(x+6)}{\log(2)}-5$

7 0

1 year ago