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hammer [34]
3 years ago
5

The scores of eighth-grade students in a math test are normally distributed with a mean of 57.5 and a standard deviation of 6.5.

From this data, we can conclude that 68% of the students received scores between and . NextReset
Mathematics
2 answers:
spayn [35]3 years ago
7 0

Answer:

44.5,70.5

Step-by-step explanation:

Empirical Rule-

  1. 68% of data falls within the one standard deviation from the mean.
  2. 95% fall within two standard deviations from the mean.
  3. 99.7% fall within three standard deviations from the mean.

Here, the normal distribution has the mean as 57.5 and standard deviation as 6.5

So the 68% of the score will lie between,

=\mu \pm 2\sigma

=57.5\pm 2(6.5)

=57.5\pm 13

=44.5,70.5

Firlakuza [10]3 years ago
5 0
Approximately 68% of a normal distribution lies within one standard deviation of the mean, so this corresponds to students with scores between (57.5-6.5,57.5+6.5)=(51,64).
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If one acute angle of a right triangle measure 37 what's the measure of the other acute angle
Ghella [55]

53°

Step-by-step:

- All angles in a triangle add up to 180°.

- Since your triangle is a right angle triangle, one of the angles are 90°.

- You already know another one, 37°.

- All you have to do to find the last one is to subtract the two you already know from 180.

180 - (90+37)

= 180 - 127

= 53

The measure of the last angle is 53°.

5 0
3 years ago
The operations manager of a large production plant would like to estimate the mean amount of time a worker takes to assemble a n
xz_007 [3.2K]

Answer:

(15,595, 16,805)

Step-by-step explanation:

We have to:

m = 16.2, sd = 3.75, n = 150

m is the mean, sd is the standard deviation and n is the sample size.

the degree of freedom would be:

n - 1 = 150 - 1 = 149

df = 149

at 95% confidence level the t is:

alpha = 1 - 95% = 1 - 0.95 = 0.05

alpha / 2 = 0.05 / 2 = 0.025

now well for t alpha / 2 (0.025) and df (149) = t = 1,976

the margin of error = E = t * sd / (n ^ (1/2))

replacing:

E = 1,976 * 3.75 / (150 ^ (1/2))

E = 0.605

The 95% confidence interval estimate of the popilation mean is:

m - E <u <m + E

16.2 - 0.605 <u <16.2 + 0.605

15,595 <u <16,805

(15,595, 16,805)

5 0
4 years ago
A car is traveling at a rate of
LUCKY_DIMON [66]

50 meters per second

3600 seconds per hour

1000 meters per km

50/1000 = 0.05

1/3600 = .0002777

0.05/0.0002777 = 180km per hour

180*4 = 720km in 4 hours


8 0
4 years ago
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jasenka [17]

Answer:

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Step-by-step explanation:

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I added in the slope formula at the bottom, just in case, so you'll see what I mean!

I hope this helps, and I explained enough! Have a great day c:

7 0
3 years ago
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The monthly salaries of a sample of 100 employees were rounded to the nearest ten dollars. they ranged from a low of $1,040 to a
never [62]
1720 - 1040 = 680
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6 0
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