Problem 4: Air flows into an open system and carries energy at the rate of 100 kW. When the air leaves the system, the energy ra
1 answer:
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Answer:
t = 6179.1 s = 102.9 min = 1.7 h
Explanation:
The energy provided by the resistance heater must be equal to the energy required to boil the water:
E = ΔQ
ηPt = mH
where.
η = efficiency = 84.5 % = 0.845
P = Power = 2.61 KW = 2610 W
t = time = ?
m = mass of water = 6.03 kg
H = Latent heat of vaporization of water = 2.26 x 10⁶ J/kg
Therefore,
(0.845)(2610 W)t = (6.03 kg)(2.26 x 10⁶ J/kg)
<u>t = 6179.1 s = 102.9 min = 1.7 h</u>
Answer:
The answer is below
Explanation:
1) The synchronous speed of an induction motor is the speed of the magnetic field of the stator. It is given by:
2) The speed of the rotor is the motor speed. The slip is given by:
3) The frequency of the rotor is given as:
4) At standstill, the speed of the motor is 0, therefore the slip is 1.
The frequency of the rotor is given as: