Asheville had about 20 more inches of rain and it rained for about 40 more days than Wichita
subtract both rainfall and days for Wichita from the same quantities in Asheville
47.71 - 28.61 = 19.1 , about 20 inches
124 - 85 = 39, about 40
both quantities rounded to the nearest 10
Answer:
One standard deviation above the mean means a z-score of 1.0. If we put this into the calculator as normalcdf(1,999) = .159
15.9 percent of the athletes would have a distance greater than 20.56 meters.
Now multiply the number of athletes by the percent.
.159 * 40 = 6.346 = about 6 athletes
c. about 6 athletes
At first Divide the figure into two rectangles, I and Il
Area of figure l is ~
Area of figure ll is ~
Area of whole figure = Area ( l + ll )
that is equal to ~
Answer:
the second choice
Step-by-step explanation:
Answer:
$1255.
Step-by-step explanation:
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