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3 years ago

If three dozen cookies cost $9, what is the cost per cookie?

Mathematics

2 answers:

e-lub [12.9K]3 years ago

5 0

i think
25 per cents

Lapatulllka [165]3 years ago

5 0

.25 each because you have three 12 dozen cookies and so you add 12 three times or times it by three which makes u have 36 total cookies and you cant divide 36 by 9 because it wouls make no since to have 4$ per cookie so you do it the other way and get $0.25

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If the 6 in 14,563 was changed to a 9 ,how much would the value change

AnnyKZ [126]

Answer:

It would change by 30 points

Step-by-step explanation: If you block the rest of the numbers you would see 63 change to 93. 93-63=30 so it would change by 30 points

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3 years ago

If I worked all these hours, how much should I be paid. It's 13.69 per hour btw each. Schedule:

Dennis_Churaev [7]

Answer:

$246.42

Step-by-step explanation:

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13.69(16) + 27.38

219.04 + 27.38

246.42

You should make $246.42.

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3 years ago

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Elan Coil [88]

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3 years ago

Read 2 more answers

Hint: Plug each number into the formula a^2 + b^2 = c^2. Then see which set of numbers balances out.

Anni [7]

Answer:

Step-by-step:

a^2+ b^2 = c^2

if we try A

6^2+8^2 = 10^2 => 64+36 = 100

7 0

2 years ago

The cost of health insurance is $1,200 per year. The cost of an operation for a dramatic injury is $500,000. The chances of some

SIZIF [17.4K]

Answer:

yes. The cost of the insurance is less than the probability cost of the operation

Step-by-step explanation:

yes. The cost of the insurance is less than the probability cost of the operation

The cost of health insurance = $1200

Cost of dramatic injury operation= $500,000

chances of need of operation= 47.3% over a 20 years period

the amount of pay insurance after 20 years= $20\times 1200= 240,00$

probable of cost operation= 0.473*500,00= $236,500

clearly the cost of insurance is less than the probable cost of operation.

5 0

3 years ago