The point 
is on the graph of the equation.
Explanation:
The equation is 
We need to determine the point is on the graph.
To determine the point is on the graph, we need to substitute the point in the equation and find whether the LHS is equal to RHS.
Thus, substituting the point in the equation , we get,
Multiplying the terms within the bracket, we have,
Adding the LHS, we have,
Thus, both sides of the equation are equal.
Hence, the point is on the graph of the equation
I’m not sure but I got 8 ^-5
The answer is C) 4x3 − 3x2 − 2x + 11
27) if a = 1/a
multiply both sides by a
a * a = 1/a * a
a^ 2 = 1
Answer is D) 1
28)
6 x 75 = 450
7 x 80 = 560
8 x 85 = 680
9 x 90 = 810
Total all students in class = 6 + 7 + 8 + 9 = 30 students
Total score of whole class:
450 + 560 + 680 + 810 = 2500
Average = 2500 /30 = 83.3 = 83 1/3
Answer is C) 83 1/3
Answer:
r = 64
Step-by-step explanation:
r = (k*t*u)/s
Where,
k = constant of proportionality
t = -12,
u= -7,
s= -4,
r= -126.
r = (k*t*u)/s
-126 = (k*-12*-7)/-4
-126 * -4 = 84k
504 = 84k
k = 504/84
k = 6
Find r when t= -8, u= 8, and s= -6.
r = (k*t*u)/s
= (6*-8*8) / -6
= -384 / -6
= 64
r = 64
